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A current of 2 ampere flows in a long, straight wire of radius 2 mm. The intensity of magnetic field at the axis of the wire is
  • a)
    μ₀/π x 103 telsa
  • b)
    μ₀/2π x 103 telsa
  • c)
    2μ₀/π x 103 telsa
  • d)
    zero
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A current of 2 ampere flows in a long, straight wire of radius 2 mm. T...
To find the intensity of the magnetic field at the axis of the wire, we can use Ampere's law. Ampere's law states that the magnetic field around a closed loop is proportional to the current passing through the loop.

The formula for the magnetic field at the axis of a long, straight wire is given by:

B = (μ₀ * I) / (2π * r)

where B is the magnetic field, μ₀ is the permeability of free space (4π × 10^-7 T·m/A), I is the current, and r is the distance from the wire.

In this case, the current (I) is given as 2 A and the radius (r) is given as 2 mm (or 0.002 m).

Plugging these values into the formula, we get:

B = (4π × 10^-7 T·m/A * 2 A) / (2π * 0.002 m)

Simplifying the equation gives:

B = (4π × 10^-7 T·m) / (2π * 0.002 m)

B = (2 × 10^-7 T·m) / (0.004 m)

B = 5 × 10^-5 T

Therefore, the intensity of the magnetic field at the axis of the wire is 5 × 10^-5 T.
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Community Answer
A current of 2 ampere flows in a long, straight wire of radius 2 mm. T...
At axis of wire magnetic field is zero
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