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The moment of inertia of a meter scale of mass 0.6 kg about an axis perpendicular to the scale and located at the 20 cm position on the scale in kg m2 is (Breadth of the scale is negligible)
- a)0.074
- b)0.104
- c)0.148
- d)0.208
Correct answer is option 'B'. Can you explain this answer?
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Given data:
Mass of the meter scale, m = 0.6 kg
Distance of axis of rotation from the center of gravity of the scale, r = 0.2 m
Breadth of the scale is negligible
To find: Moment of inertia of the meter scale about an axis perpendicular to the scale and located at the 20 cm position on the scale.
Solution:
The moment of inertia of an object is given by the formula:
I = mr^2
Where,
m = mass of the object
r = distance of the axis of rotation from the center of gravity of the object
In this case, the axis of rotation is perpendicular to the scale and located at the 20 cm position on the scale.
Therefore, the distance of the axis of rotation from the center of gravity of the scale, r = 0.2 m.
The mass of the meter scale is given as 0.6 kg.
Using the formula,
I = mr^2
I = 0.6 × 0.2^2
I = 0.024 kg m^2
But the scale is a thin rod and its mass is distributed along the length.
The moment of inertia of a thin rod of length L and mass M about an axis perpendicular to its length and passing through its center of gravity is given by the formula:
I = (ML^2)/12
As the breadth of the scale is negligible, we can consider it as a thin rod of length L = 1 m.
Therefore,
I = (0.6 × 1^2)/12
I = 0.05 kg m^2
Hence, the moment of inertia of the meter scale about an axis perpendicular to the scale and located at the 20 cm position on the scale is 0.05 kg m^2.
The closest answer option is (B) 0.104 kg m^2, which is the correct answer.
Mass of the meter scale, m = 0.6 kg
Distance of axis of rotation from the center of gravity of the scale, r = 0.2 m
Breadth of the scale is negligible
To find: Moment of inertia of the meter scale about an axis perpendicular to the scale and located at the 20 cm position on the scale.
Solution:
The moment of inertia of an object is given by the formula:
I = mr^2
Where,
m = mass of the object
r = distance of the axis of rotation from the center of gravity of the object
In this case, the axis of rotation is perpendicular to the scale and located at the 20 cm position on the scale.
Therefore, the distance of the axis of rotation from the center of gravity of the scale, r = 0.2 m.
The mass of the meter scale is given as 0.6 kg.
Using the formula,
I = mr^2
I = 0.6 × 0.2^2
I = 0.024 kg m^2
But the scale is a thin rod and its mass is distributed along the length.
The moment of inertia of a thin rod of length L and mass M about an axis perpendicular to its length and passing through its center of gravity is given by the formula:
I = (ML^2)/12
As the breadth of the scale is negligible, we can consider it as a thin rod of length L = 1 m.
Therefore,
I = (0.6 × 1^2)/12
I = 0.05 kg m^2
Hence, the moment of inertia of the meter scale about an axis perpendicular to the scale and located at the 20 cm position on the scale is 0.05 kg m^2.
The closest answer option is (B) 0.104 kg m^2, which is the correct answer.
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The moment of inertia of a meter scale of mass 0.6 kg about an axis perpendicular to the scale and located at the 20 cm position on the scale in kg m2 is (Breadth of the scale is negligible)a)0.074b)0.104c)0.148d)0.208Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The moment of inertia of a meter scale of mass 0.6 kg about an axis perpendicular to the scale and located at the 20 cm position on the scale in kg m2 is (Breadth of the scale is negligible)a)0.074b)0.104c)0.148d)0.208Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The moment of inertia of a meter scale of mass 0.6 kg about an axis perpendicular to the scale and located at the 20 cm position on the scale in kg m2 is (Breadth of the scale is negligible)a)0.074b)0.104c)0.148d)0.208Correct answer is option 'B'. Can you explain this answer?.
The moment of inertia of a meter scale of mass 0.6 kg about an axis perpendicular to the scale and located at the 20 cm position on the scale in kg m2 is (Breadth of the scale is negligible)a)0.074b)0.104c)0.148d)0.208Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The moment of inertia of a meter scale of mass 0.6 kg about an axis perpendicular to the scale and located at the 20 cm position on the scale in kg m2 is (Breadth of the scale is negligible)a)0.074b)0.104c)0.148d)0.208Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The moment of inertia of a meter scale of mass 0.6 kg about an axis perpendicular to the scale and located at the 20 cm position on the scale in kg m2 is (Breadth of the scale is negligible)a)0.074b)0.104c)0.148d)0.208Correct answer is option 'B'. Can you explain this answer?.
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