Two equal charges are separated by a distance d. A third charge placed on a perpendicular bisector at x distance will experience maximum coulomb force when A) x= d÷√2 B. x=d÷2 C. x= d÷2√2 D. x= d÷2√3 Please show me the solution?

Question

Answer

Answer

(c)  x=d/2√2

Answer

Solution:

Given:
- Two equal charges separated by a distance d
- A third charge placed on a perpendicular bisector at x distance

To find:
- The distance x at which the third charge will experience maximum coulomb force

Explanation:
- When the third charge is placed on the perpendicular bisector, it experiences forces from both charges which are equal in magnitude but opposite in direction.
- The net force experienced by the third charge is the vector sum of the forces due to the two charges.

Calculating the net force:
- The force due to each charge is given by Coulomb's law: F = k*q1*q2/r^2, where k is the Coulomb constant, q1 and q2 are the charges, and r is the distance between the charges.
- Since the charges are equal, the forces are also equal in magnitude.
- The net force experienced by the third charge is maximum when the two forces are along the same line. This occurs when the perpendicular bisector divides the distance between the two charges in the ratio 1:2.

Calculation:
- The distance x at which the third charge will experience maximum coulomb force is x = d/2.

Therefore, the correct answer is:
B) x = d/2

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