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Two fixed charges A and B of 5micro coulomb each are separated by a distance of 6m . C is the midpoint of the line joining A and B .A charge Q of -5 micro coulomb is shot perpendicular to the line joining A and B through C with kinetic energy 0.06 J. The charge Q comes to rest at a point D. The distance CD is?
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Two fixed charges A and B of 5micro coulomb each are separated by a di...
Problem: Find the distance CD when a charge Q of -5 micro coulomb is shot perpendicular to the line joining A and B through C with kinetic energy 0.06 J.
Given:
- Charges A and B with 5 micro coulomb each.
- Distance between A and B is 6m.
- Charge Q of -5 micro coulomb.
- Charge Q is shot through C.
- Kinetic energy of Q is 0.06 J.
- Charge Q comes to rest at point D.
Solution:
1. Calculate the potential energy of charge Q at point C.
- The potential energy of Q at point C is given by the formula: PE = kQq/r, where k is the Coulomb constant (9 x 10^9 Nm^2/C^2), Q and q are the charges, and r is the distance between them.
- Since Q and A have opposite charges, the potential energy of Q at point C is: PE = (9 x 10^9 Nm^2/C^2) x (-5 x 10^-6 C) x (5 x 10^-6 C) / (3m) = -7.5 x 10^-3 J.
2. Calculate the potential energy of charge Q at point D.
- The potential energy of Q at point D is also given by the formula: PE = kQq/r, where r is now the distance between Q and B.
- Since Q and B have the same charge, the potential energy of Q at point D is: PE = (9 x 10^9 Nm^2/C^2) x (-5 x 10^-6 C) x (5 x 10^-6 C) / (3m + CD) = -7.5 x 10^-3 J + (9 x 10^9 Nm^2/C^2) x (-5 x 10^-6 C) x (5 x 10^-6 C) / CD.
3. Use the conservation of energy principle to find the distance CD.
- The kinetic energy of Q at point C is equal to the potential energy of Q at point D: KE = PE.
- Substituting the values, we get: 0.06 J = -7.5 x 10^-3 J + (9 x 10^9 Nm^2/C^2) x (-5 x 10^-6 C) x (5 x 10^-6 C) / CD.
- Rearranging and solving for CD, we get: CD = 1.2 m.
Answer: The distance CD is 1.2 m.
Given:
- Charges A and B with 5 micro coulomb each.
- Distance between A and B is 6m.
- Charge Q of -5 micro coulomb.
- Charge Q is shot through C.
- Kinetic energy of Q is 0.06 J.
- Charge Q comes to rest at point D.
Solution:
1. Calculate the potential energy of charge Q at point C.
- The potential energy of Q at point C is given by the formula: PE = kQq/r, where k is the Coulomb constant (9 x 10^9 Nm^2/C^2), Q and q are the charges, and r is the distance between them.
- Since Q and A have opposite charges, the potential energy of Q at point C is: PE = (9 x 10^9 Nm^2/C^2) x (-5 x 10^-6 C) x (5 x 10^-6 C) / (3m) = -7.5 x 10^-3 J.
2. Calculate the potential energy of charge Q at point D.
- The potential energy of Q at point D is also given by the formula: PE = kQq/r, where r is now the distance between Q and B.
- Since Q and B have the same charge, the potential energy of Q at point D is: PE = (9 x 10^9 Nm^2/C^2) x (-5 x 10^-6 C) x (5 x 10^-6 C) / (3m + CD) = -7.5 x 10^-3 J + (9 x 10^9 Nm^2/C^2) x (-5 x 10^-6 C) x (5 x 10^-6 C) / CD.
3. Use the conservation of energy principle to find the distance CD.
- The kinetic energy of Q at point C is equal to the potential energy of Q at point D: KE = PE.
- Substituting the values, we get: 0.06 J = -7.5 x 10^-3 J + (9 x 10^9 Nm^2/C^2) x (-5 x 10^-6 C) x (5 x 10^-6 C) / CD.
- Rearranging and solving for CD, we get: CD = 1.2 m.
Answer: The distance CD is 1.2 m.
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Two fixed charges A and B of 5micro coulomb each are separated by a di...
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Two fixed charges A and B of 5micro coulomb each are separated by a distance of 6m . C is the midpoint of the line joining A and B .A charge Q of -5 micro coulomb is shot perpendicular to the line joining A and B through C with kinetic energy 0.06 J. The charge Q comes to rest at a point D. The distance CD is?
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Two fixed charges A and B of 5micro coulomb each are separated by a distance of 6m . C is the midpoint of the line joining A and B .A charge Q of -5 micro coulomb is shot perpendicular to the line joining A and B through C with kinetic energy 0.06 J. The charge Q comes to rest at a point D. The distance CD is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two fixed charges A and B of 5micro coulomb each are separated by a distance of 6m . C is the midpoint of the line joining A and B .A charge Q of -5 micro coulomb is shot perpendicular to the line joining A and B through C with kinetic energy 0.06 J. The charge Q comes to rest at a point D. The distance CD is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two fixed charges A and B of 5micro coulomb each are separated by a distance of 6m . C is the midpoint of the line joining A and B .A charge Q of -5 micro coulomb is shot perpendicular to the line joining A and B through C with kinetic energy 0.06 J. The charge Q comes to rest at a point D. The distance CD is?.
Two fixed charges A and B of 5micro coulomb each are separated by a distance of 6m . C is the midpoint of the line joining A and B .A charge Q of -5 micro coulomb is shot perpendicular to the line joining A and B through C with kinetic energy 0.06 J. The charge Q comes to rest at a point D. The distance CD is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two fixed charges A and B of 5micro coulomb each are separated by a distance of 6m . C is the midpoint of the line joining A and B .A charge Q of -5 micro coulomb is shot perpendicular to the line joining A and B through C with kinetic energy 0.06 J. The charge Q comes to rest at a point D. The distance CD is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two fixed charges A and B of 5micro coulomb each are separated by a distance of 6m . C is the midpoint of the line joining A and B .A charge Q of -5 micro coulomb is shot perpendicular to the line joining A and B through C with kinetic energy 0.06 J. The charge Q comes to rest at a point D. The distance CD is?.
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