The number of Gram atoms in 8 g of helium are?

Question

Answer

Atomic mass of Helium is 4. So if you take 4 grams of Helium atom,then the number of atoms in it will be 6.0203x10^23,that is avogadro number. If you take 8 grams of Helium,then it will be double of avogadro number. Ans: 2

Answer

Given mass= 8
Atomic mass=4
Gram atoms or moles in 8g=4/8
=2 Gram atoms

Answer

Calculation:

To find the number of gram atoms in 8 g of helium, we need to follow a few steps. Let's break down the calculation into smaller parts:

Step 1: Calculate the molar mass of helium

The molar mass of an element is the mass of one mole of that element. To find the molar mass of helium, we can refer to the periodic table. The atomic mass of helium is approximately 4 g/mol.

Step 2: Convert grams of helium to moles

To convert grams of helium to moles, we can use the formula:

Number of moles = Mass of substance / Molar mass

In this case, the mass of helium is 8 g, and the molar mass of helium is 4 g/mol.

Number of moles = 8 g / 4 g/mol = 2 mol

Step 3: Convert moles to gram atoms

A mole of any substance contains 6.022 × 10^23 particles, which is known as Avogadro's number. Therefore, we can use Avogadro's number to convert moles to gram atoms.

Number of gram atoms = Number of moles × Avogadro's number

In this case, the number of moles is 2 mol.

Number of gram atoms = 2 mol × 6.022 × 10^23 atoms/mol = 1.2044 × 10^24 gram atoms

Answer:

Therefore, there are approximately 1.2044 × 10^24 gram atoms in 8 g of helium.

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