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Two dice are thrown at the same time and the product of numbers appearing on them is noted find the probability that the product of number lies between 8 and 13?
Most Upvoted Answer
Two dice are thrown at the same time and the product of numbers appear...

Total no.of possible outcomes = 6^2 = 36
i.e. (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)


now product of  no. lie between 8-13 are :- (5,2) (6,2)(3,3)(3,4)(2,5)(2,6) (4,3) = 7
so probability =7/36
Community Answer
Two dice are thrown at the same time and the product of numbers appear...
Solution:

To find the probability that the product of the numbers on two dice lies between 8 and 13, we need to determine the number of favorable outcomes and the total number of possible outcomes.

Step 1: Determining the favorable outcomes

To find the favorable outcomes, we need to identify all the possible combinations of numbers on two dice whose product lies between 8 and 13. The possible outcomes are as follows:

- (2,4) - Product = 8
- (3,3) - Product = 9
- (2,6) - Product = 12

Therefore, there are 3 favorable outcomes.

Step 2: Determining the total number of possible outcomes

To find the total number of possible outcomes, we need to consider all the possible combinations of numbers on two dice. Each die has 6 faces, so there are 6 possible outcomes for each die. Therefore, the total number of possible outcomes is 6 * 6 = 36.

Step 3: Calculating the probability

The probability can be calculated using the formula:

Probability = (Number of favorable outcomes) / (Total number of possible outcomes)

Substituting the values, we get:

Probability = 3 / 36

Simplifying the fraction, we get:

Probability = 1 / 12

Therefore, the probability that the product of the numbers on two dice lies between 8 and 13 is 1/12.

Summary:

- To find the probability, we determined the number of favorable outcomes and the total number of possible outcomes.
- There are 3 favorable outcomes: (2,4), (3,3), and (2,6).
- There are 36 total possible outcomes, as each die has 6 faces.
- Using the formula Probability = (Number of favorable outcomes) / (Total number of possible outcomes), we calculated the probability to be 1/12.
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Two dice are thrown at the same time and the product of numbers appearing on them is noted find the probability that the product of number lies between 8 and 13?
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