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Counters marked 1, 2, 3 are placed in a bag and one of them is withdrawn and replaced. The operation being repeated three times, what is the chance of obtaining a total of 6 in these three operations?
- a)11/27
- b)7/27
- c)1/27
- d)5/14
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Counters marked 1, 2, 3 are placed in a bag and one of them is withdra...
6 can be written in 7 ways .
6=1+2+3;
6=1+3+2;
6=2+1+3;
6=2+3+1;
6=3+2+1;
6=3+1+2;
6=2+2+2;
total above cases=7.
number of ways one can withdrawn and replaced(3 times) = 27.( 111, 112, 113, 121, 122, 123, 131, 132, 133, 211, 212, 213, 221, 222, 223, 231, 232, 233, 311, 312, 313, 321, 322, 323, 331, 332, 333).
so probability(chance) become 7/27.
Most Upvoted Answer
Counters marked 1, 2, 3 are placed in a bag and one of them is withdra...
To solve this problem, we can use the concept of probability. Let's break down the problem into smaller steps:
Step 1: Determine the total number of possible outcomes.
Since each counter can be withdrawn and replaced three times, there are a total of 3^3 = 27 possible outcomes.
Step 2: Determine the number of favorable outcomes.
To obtain a total of 6, we need to find the combinations of counters that add up to 6. The possible combinations are:
1 + 2 + 3 = 6
2 + 1 + 3 = 6
3 + 2 + 1 = 6
Therefore, there are three favorable outcomes.
Step 3: Calculate the probability.
The probability is determined by dividing the number of favorable outcomes by the total number of possible outcomes.
Probability = Number of Favorable Outcomes / Total Number of Possible Outcomes
Probability = 3 / 27
Simplifying further, we get:
Probability = 1 / 9
Therefore, the chance of obtaining a total of 6 in these three operations is 1/9.
However, none of the given options match with our answer. Let's re-evaluate the options and try to find the correct answer.
Option A: 11/27
Option B: 7/27
Option C: 1/27
Option D: 5/14
Since our calculated probability is 1/9, none of the options match our answer. It seems that there might be an error in the options provided or in our calculations. Please double-check the options or the given information to find the correct answer.
Step 1: Determine the total number of possible outcomes.
Since each counter can be withdrawn and replaced three times, there are a total of 3^3 = 27 possible outcomes.
Step 2: Determine the number of favorable outcomes.
To obtain a total of 6, we need to find the combinations of counters that add up to 6. The possible combinations are:
1 + 2 + 3 = 6
2 + 1 + 3 = 6
3 + 2 + 1 = 6
Therefore, there are three favorable outcomes.
Step 3: Calculate the probability.
The probability is determined by dividing the number of favorable outcomes by the total number of possible outcomes.
Probability = Number of Favorable Outcomes / Total Number of Possible Outcomes
Probability = 3 / 27
Simplifying further, we get:
Probability = 1 / 9
Therefore, the chance of obtaining a total of 6 in these three operations is 1/9.
However, none of the given options match with our answer. Let's re-evaluate the options and try to find the correct answer.
Option A: 11/27
Option B: 7/27
Option C: 1/27
Option D: 5/14
Since our calculated probability is 1/9, none of the options match our answer. It seems that there might be an error in the options provided or in our calculations. Please double-check the options or the given information to find the correct answer.
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Counters marked 1, 2, 3 are placed in a bag and one of them is withdrawn and replaced. The operation being repeated three times, what is the chance of obtaining a total of 6 in these three operations?a)11/27b)7/27c)1/27d)5/14Correct answer is option 'B'. Can you explain this answer?
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Counters marked 1, 2, 3 are placed in a bag and one of them is withdrawn and replaced. The operation being repeated three times, what is the chance of obtaining a total of 6 in these three operations?a)11/27b)7/27c)1/27d)5/14Correct answer is option 'B'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Counters marked 1, 2, 3 are placed in a bag and one of them is withdrawn and replaced. The operation being repeated three times, what is the chance of obtaining a total of 6 in these three operations?a)11/27b)7/27c)1/27d)5/14Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Counters marked 1, 2, 3 are placed in a bag and one of them is withdrawn and replaced. The operation being repeated three times, what is the chance of obtaining a total of 6 in these three operations?a)11/27b)7/27c)1/27d)5/14Correct answer is option 'B'. Can you explain this answer?.
Counters marked 1, 2, 3 are placed in a bag and one of them is withdrawn and replaced. The operation being repeated three times, what is the chance of obtaining a total of 6 in these three operations?a)11/27b)7/27c)1/27d)5/14Correct answer is option 'B'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Counters marked 1, 2, 3 are placed in a bag and one of them is withdrawn and replaced. The operation being repeated three times, what is the chance of obtaining a total of 6 in these three operations?a)11/27b)7/27c)1/27d)5/14Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Counters marked 1, 2, 3 are placed in a bag and one of them is withdrawn and replaced. The operation being repeated three times, what is the chance of obtaining a total of 6 in these three operations?a)11/27b)7/27c)1/27d)5/14Correct answer is option 'B'. Can you explain this answer?.
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