Manju is at a fixed point, from where she goes 20 metres towards West....
**Given Information:**
- Manju starts at a fixed point.
- Manju moves 20 meters towards the west.
- Manju then moves 10 meters towards the north.
- Manju then moves 35 meters towards the east.
- Manju then moves 5 meters towards the south.
- Manju finally moves 15 meters towards the west.
**To Find:**
The distance of Manju from the fixed point.
**Solution:**
To find the distance of Manju from the fixed point, we need to determine the net displacement of Manju.
Let's analyze the given information step by step:
1. Manju moves 20 meters towards the west. This means she is 20 meters away from the fixed point in the west direction.
2. Manju then moves 10 meters towards the north. This means she changes her direction and moves 10 meters towards the north. Now, Manju is 10 meters north and 20 meters west from the fixed point.
3. Manju then moves 35 meters towards the east. This means she changes her direction again and moves 35 meters towards the east. Now, Manju is 10 meters north, 15 meters east, and 20 meters west from the fixed point.
4. Manju then moves 5 meters towards the south. This means she changes her direction once again and moves 5 meters towards the south. Now, Manju is 10 meters north, 15 meters east, 20 meters west, and 5 meters south from the fixed point.
5. Manju finally moves 15 meters towards the west. This means she changes her direction for the last time and moves 15 meters towards the west. Now, Manju is 10 meters north, 5 meters east, and 20 meters west from the fixed point.
Based on the given information, we can see that Manju is 20 meters away from the fixed point in the west direction. Therefore, the distance of Manju from the fixed point is 20 meters.
Hence, the correct answer is option A) 20 meters.
Manju is at a fixed point, from where she goes 20 metres towards West....
Let's analyze Manju's movements step by step:
Initial position:
- Manju is at a fixed point (let's call this point A).
First Movement:
- She goes 20 meters towards West.
- Let's call this point B.
Second Movement:
- From point B, she goes 10 meters towards North.
- Let's call this point C.
Third Movement:
- From point C, she goes 35 meters towards East.
- Let's call this point D.
Fourth Movement:
- From point D, she goes 5 meters towards South.
- Let's call this point E.
Fifth Movement:
- From point E, she goes 15 meters towards West.
- Let's call this point F.
Now, we need to find the distance between point A and point F.
- Since Manju initially moved 20 meters West and then moved an additional 15 meters West in her last movement, she is a total of 35 meters West from her starting point A.
- However, she also moved 35 meters East from point C to point D, which brings her back to the same vertical line as her starting point A.
- Considering her North and South movements, she moved a total of 10 meters North and 5 meters South, resulting in a net movement of 5 meters North from point A.
Now, we can use the Pythagorean theorem to find the distance between points A and F:
AF = √((Horizontal Distance)² + (Vertical Distance)²)
AF = √((0 meters)² + (5 meters)²)
AF = √(25)
AF = 5 meters
So, Manju is 5 meters away from her initial fixed point.
Answer: **A: 5 km** (Note: It should be "5 meters" instead of "5 km" in the options)