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what if the number is not a perfect cube root?
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what if the number is not a perfect cube root? Related: Cube root of ...
Let’s define something called a Digital root. It is the sum obtained after iteratively adding the digits of a number, till a single digit remains.For example, digital root of 345= 3 + 4 + 5 =12.345=3+4+5=12.Now, 12 = 1+2 = 3.12=1+2=3.So, digital root of 345=3.345=3.Similarly, for 987679987679, we have, 9+8+7+6+7+9=469+8+7+6+7+9=46 and 4+6=104+6=10and 1+0=11+0=1So, digital root for 987679=1987679=1Now, we are somewhat familiar with the concept.Turns out that for all perfect cubes, the digital root will either be 1,8,9.1,8,9.0 0is not included as 0 0is a perfect cube of itself. Anyways, if for a number xx you get a digital root that is not 1,8,91,8,9, you can confidently say that xx is NOT a perfect cube.What if the digital root is 1,8,91,8,9 ??Then, the number may or may not be a perfect cube. You will now have to use prime factorization method to verify. Be very careful here.Example, for 102251 the digital root is 2 so, definitely it is not a perfect cube.However. for 100 the digital root is 1, so it may or may not be a perfect cube.
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