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If the reduced bearing of a line AB is N60°W and length is 100 m, then the latitude and departure respectively of the line AB will be
  • a)
    +50 m, +86.6 m
  • b)
    +86.6 m, -50 m
  • c)
    +50 m, -86.6 m
  • d)
    +70.7 m, -50 m
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If the reduced bearing of a line AB is N60°W and length is 100 m,...
Latitude = LcosA = 100 cos(300) = 50 Departure = LsinA = 100 sin(300) = -86.6

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Most Upvoted Answer
If the reduced bearing of a line AB is N60°W and length is 100 m,...
Given:
Reduced bearing of line AB = N60W
Length of line AB = 100 m

To find:
Latitude and departure of line AB

Solution:
Step 1: Convert the reduced bearing into whole circle bearing
- Whole circle bearing = 360° - Reduced bearing
- Whole circle bearing = 360° - N60W
- Whole circle bearing = S30E

Step 2: Calculate the latitude and departure using the following formulas:
- Latitude = Length x cos(bearing)
- Departure = Length x sin(bearing)

Substituting the values, we get:
- Latitude = 100 x cos(S30E) = 86.6 m
- Departure = 100 x sin(S30E) = -50 m

Therefore, the latitude and departure of line AB are 86.6 m and -50 m respectively.

Answer: Option B.
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Community Answer
If the reduced bearing of a line AB is N60°W and length is 100 m,...
Latitude=100cos60=50
departure=100sin60=86.6
due to direction of angle departure will be negative

Hence Option (C) is correct:

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Question Description
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