Remaining T.S.A of the Solid Cylinder

Given:
Height of the solid cylinder = 2.4 cm
Diameter of the solid cylinder = 1.4 cm

To find the total surface area (T.S.A) of the remaining solid, we need to consider the surface area of the original solid cylinder and subtract the surface area of the hollowed-out cavity.

Step 1: Calculate the surface area of the original solid cylinder.
The surface area of a cylinder is given by the formula:
T.S.A = 2πrh + πr²
where r is the radius of the cylinder and h is the height of the cylinder.

Given:
Diameter = 1.4 cm
Radius (r) = Diameter/2 = 1.4/2 = 0.7 cm
Height (h) = 2.4 cm

Substituting the values into the formula:
T.S.A of the original solid cylinder = 2π(0.7)(2.4) + π(0.7)²
T.S.A = 4.8π + 0.49π
T.S.A = 5.29π

Step 2: Calculate the surface area of the hollowed-out cavity.
Since the clinical cavity has the same height and diameter as the original solid cylinder, the dimensions of the hollowed-out cavity will also be the same.

Using the same formula as before:
T.S.A of the hollowed-out cavity = 2πrh + πr²
T.S.A = 2π(0.7)(2.4) + π(0.7)²
T.S.A = 4.8π + 0.49π
T.S.A = 5.29π

Step 3: Calculate the remaining T.S.A of the solid.
To find the remaining T.S.A of the solid, we subtract the surface area of the hollowed-out cavity from the surface area of the original solid cylinder.

Remaining T.S.A = T.S.A of the original solid cylinder - T.S.A of the hollowed-out cavity
Remaining T.S.A = 5.29π - 5.29π
Remaining T.S.A = 0 cm²

Therefore, the T.S.A of the remaining solid to the nearest cm² is 0 cm².