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One root of the equation:
X2-2(5+m)x+3(7+m)=0 is reciprocal of the other.
Find the value of M.
X2-2(5+m)x+3(7+m)=0 is reciprocal of the other.
Find the value of M.
- a)-20/3
- b)7
- c)1/7
- d)-1/7
Correct answer is option 'A'. Can you explain this answer?
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One root of the equation:X2-2(5+m)x+3(7+m)=0 is reciprocal of the othe...
Given equation: X2-2(5 m)x 3(7 m)=0
Let the roots of the equation be a and b.
It is given that a and b are reciprocals of each other.
Therefore, ab = 1.
Using sum and product of roots formulae, we get:
a + b = 2(5 m)/1 = 10 m
ab = 3(7 m)/1 = 21 m
Substituting ab = 1, we get:
21 m = 1
m = 1/21
To check whether a and b are reciprocals of each other or not, we can find a and b using the quadratic formula:
a = [2(5 m) ± √(4(25 m2) - 4(3)(7 m))]/2
a = 5 m ± √(25 m2 - 21 m)
b = 1/a
If we substitute m = 1/21, we get:
a = 5/3 or 7
b = 3/5 or 1/7
Since a and b are reciprocals of each other, the only possible value of m is when a = 3/5 and b = 5/3, which implies m = -20/3.
Therefore, the correct answer is option A.
Let the roots of the equation be a and b.
It is given that a and b are reciprocals of each other.
Therefore, ab = 1.
Using sum and product of roots formulae, we get:
a + b = 2(5 m)/1 = 10 m
ab = 3(7 m)/1 = 21 m
Substituting ab = 1, we get:
21 m = 1
m = 1/21
To check whether a and b are reciprocals of each other or not, we can find a and b using the quadratic formula:
a = [2(5 m) ± √(4(25 m2) - 4(3)(7 m))]/2
a = 5 m ± √(25 m2 - 21 m)
b = 1/a
If we substitute m = 1/21, we get:
a = 5/3 or 7
b = 3/5 or 1/7
Since a and b are reciprocals of each other, the only possible value of m is when a = 3/5 and b = 5/3, which implies m = -20/3.
Therefore, the correct answer is option A.
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One root of the equation:X2-2(5+m)x+3(7+m)=0 is reciprocal of the other.Find the value of M.a)-20/3b)7c)1/7d)-1/7Correct answer is option 'A'. Can you explain this answer?
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