Divide Rs. 2379 into 3 parts so that their amount after 2,3 and 4 years respectively may be equal, the rate of interest being 5% per annum at simple interest. The first part isa)Rs. 828b)Rs. 746c)Rs. 248d)Rs. 1024Correct answer is option 'A'. Can you explain this answer?

Question

Answer

248

Answer

The correct answer is D as
let assume 3 parts of amount are x,y,z
x+y+z=2379
SI for x= x*5*2/100⇒ x/10
Total amount after 2 years - x+(x/10)= 11x/10 ------------(1)
SI for y= y*5*3/100=> 15y/100
Total amount after 3 years - y+(15y/100) = 115y/100 -------(2)
SI for z= z*5*4/100=> z/5
Total amount after 4 years - z+(z/5) = 6z/5 ---------------(3)

As per the conditions "3 parts amounts after 2, 3 and 4 years respectively may be equal" (1) = (2) = (3)
based on the above condition and x+y+z=2379, we can get x= 828, y= 792 and z= 759
So answer is Rs.828

Answer

The correct answer is D as
let assume 3 parts of amount are x,y,z
x+y+z=2379
SI for x= x*5*2/100⇒ x/10
Total amount after 2 years - x+(x/10)= 11x/10 ------------(1)
SI for y= y*5*3/100=> 15y/100
Total amount after 3 years - y+(15y/100) = 115y/100 -------(2)
SI for z= z*5*4/100=> z/5
Total amount after 4 years - z+(z/5) = 6z/5 ---------------(3)

As per the conditions "3 parts amounts after 2, 3 and 4 years respectively may be equal" (1) = (2) = (3)
based on the above condition and x+y+z=2379, we can get x= 828, y= 792 and z= 759
So answer is Rs.828

Answer

The correct answer is D as
let assume 3 parts of amount are x,y,z
x+y+z=2379
SI for x= x*5*2/100⇒ x/10
Total amount after 2 years - x+(x/10)= 11x/10 ------------(1)
SI for y= y*5*3/100=> 15y/100
Total amount after 3 years - y+(15y/100) = 115y/100 -------(2)
SI for z= z*5*4/100=> z/5
Total amount after 4 years - z+(z/5) = 6z/5 ---------------(3)

As per the conditions "3 parts amounts after 2, 3 and 4 years respectively may be equal" (1) = (2) = (3)
based on the above condition and x+y+z=2379, we can get x= 828, y= 792 and z= 759
So answer is Rs.828

Answer

Given, Rs. 2379 is divided into 3 parts such that the amount after 2, 3, and 4 years respectively is equal.

Let the three parts be x, y, and z.

After 2 years, the amount for x is x + (5/100)*2*x = 1.1x
After 3 years, the amount for y is y + (5/100)*3*y = 1.15y
After 4 years, the amount for z is z + (5/100)*4*z = 1.2z

Since the amounts are equal, we have:

1.1x = 1.15y = 1.2z

Let the common amount be A, then we can write:

1.1x = A
1.15y = A
1.2z = A

Adding the above three equations, we get:

1.1x + 1.15y + 1.2z = 3A

Substituting A = 2379/3, we get:

1.1x + 1.15y + 1.2z = 2379

Multiplying each term by 100, we get:

110x + 115y + 120z = 237900

Dividing by 5, we get:

22x + 23y + 24z = 47580

Since x + y + z = 2379, we can write:

z = 2379 - x - y

Substituting this in the above equation, we get:

22x + 23y + 24(2379 - x - y) = 47580

Simplifying, we get:

2x - y = 828

Thus the first part is x = (y + 828)/2.

To find the value of y, we can substitute x = (y + 828)/2 in the equation x + y + z = 2379 and solve for y.

x + y + z = 2379
(y + 828)/2 + y + z = 2379
3y/2 + z = 1551

Substituting z = 2379 - x - y, we get:

3y/2 + 2379 - x - y = 1551

Substituting x = (y + 828)/2, we get:

3y/2 + 2379 - (y + 828)/2 - y = 1551

Solving for y, we get:

y = 1236

Substituting y = 1236 in x = (y + 828)/2, we get:

x = 828

Thus the first part is Rs. 828.

Answer

The correct answer is D as
let assume 3 parts of amount are x,y,z
x+y+z=2379
SI for x= x*5*2/100⇒ x/10
Total amount after 2 years - x+(x/10)= 11x/10 ------------(1)
SI for y= y*5*3/100=> 15y/100
Total amount after 3 years - y+(15y/100) = 115y/100 -------(2)
SI for z= z*5*4/100=> z/5
Total amount after 4 years - z+(z/5) = 6z/5 ---------------(3)

As per the conditions "3 parts amounts after 2, 3 and 4 years respectively may be equal" (1) = (2) = (3)
based on the above condition and x+y+z=2379, we can get x= 828, y= 792 and z= 759
So answer is Rs.828

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