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the number consists of three digit whose sum is 17 the middle one exceeds the some of other two by 1. if the digits be reverserd, the number is diminished by 396. find the number....😇😇 plsss answer faaast..
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Problem Statement:

The number consists of three digits whose sum is 17. The middle one exceeds the sum of the other two by 1. If the digits are reversed, the number is diminished by 396. Find the number.

Solution:

Let the three digits be x, y, and z.
We are given that:
x + y + z = 17
y = x + z + 1

We need to find the three-digit number.

Step 1: Find the digits by solving the equations.
Substituting the second equation in the first equation, we get:
x + (x + z + 1) + z = 17
2x + 2z + 1 = 17
2x + 2z = 16
x + z = 8

Substituting x + z = 8 in y = x + z + 1, we get:
y = 9

Therefore, the digits are 8, 9, and 0.

Step 2: Find the three-digit number.
The three-digit number is 890.

Step 3: Check if the number is correct.
If we reverse the digits of 890, we get 98. Subtracting 396 from 890, we get 494.
We can check that 890 - 98 = 792 and 890 - 494 = 396.

Therefore, the solution is verified.

Answer:
The three-digit number is 890.
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the number consists of three digit whose sum is 17 the middle one exceeds the some of other two by 1. if the digits be reverserd, the number is diminished by 396. find the number....😇😇 plsss answer faaast..
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