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A copper wire is stretched to double its length keeping the volume seen if the original resistance of the wire is 4 ohm what is the final resistance?
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A copper wire is stretched to double its length keeping the volume see...
Understanding Resistance in a Stretched Wire
When a copper wire is stretched to double its length while keeping its volume constant, its resistance changes. Let’s analyze this phenomenon step by step.
Initial Resistance
- The original resistance (R1) of the wire is given as 4 ohms.
Volume Conservation
- When the wire is stretched to double its length (L), the volume (V) remains constant.
- Volume formula: V = A × L (where A is the cross-sectional area).
Effects of Stretching
- When the length is doubled (L becomes 2L), the volume remains constant:
- A1 × L = A2 × 2L
- This implies A2 = A1/2, indicating that the cross-sectional area is halved.
Resistance Formula
- Resistance (R) is given by the formula:
R = ρ × (L/A)
where ρ is the resistivity of the material, L is the length, and A is the cross-sectional area.
Calculating Final Resistance
- With the new length (2L) and new area (A1/2):
R2 = ρ × (2L/(A1/2))
R2 = ρ × (4L/A1)
- Given that R1 = ρ × (L/A1) = 4 ohms, we can substitute:
R2 = 4 × 4 = 16 ohms.
Final Result
- The final resistance of the stretched wire is 16 ohms.
This demonstrates how stretching a wire affects its resistance due to changes in length and cross-sectional area while conserving volume.
Community Answer
A copper wire is stretched to double its length keeping the volume see...
16ohm
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A copper wire is stretched to double its length keeping the volume seen if the original resistance of the wire is 4 ohm what is the final resistance?
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