Fathers age is 5 times his sons age. 4 years back the father was 9 tim...
Lets assume son's age = x years.
so father's age = 5x years
4 years back:
son age = (x-4) years.
father's age = (5x-4) years
as per Condition given
(5x-4) = 9*(x-4)
=> 5x - 4 = 9x - 36
=> (9x-5x) = 36 - 4
=> 4x = 32 => x = 8
So father's present age = 5 * 8 = 40 years.
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Fathers age is 5 times his sons age. 4 years back the father was 9 tim...
Problem Solving:
Let the present age of the son be x. Then, the present age of the father will be 5x.
Four years back, the father's age was 5x - 4, and the son's age was x - 4.
According to the problem, the father's age was 9 times older than the son's age:
5x - 4 = 9(x - 4)
5x - 4 = 9x - 36
4x = 32
x = 8
Therefore, the present age of the son is 8 years, and the present age of the father is 5x = 40 years.
Solution:
Present age of the son = x
Present age of the father = 5x
Four years back, the father's age = 5x - 4
Four years back, the son's age = x - 4
According to the problem, 4 years back the father was 9 times older than the son:
5x - 4 = 9(x - 4)
5x - 4 = 9x - 36
4x = 32
x = 8
Therefore, the present age of the son is 8 years.
The present age of the father = 5x = 5 × 8 = 40 years.
Hence, the correct option is (c) 40 years.