Two cyclists start simultaneously towards each other from Aurangabad a...
Let person A be the one moving from aurangabad and N moving from Ellora
Lets say they meet at a point C which is x km away from aurangabad and (28 - x) km away from Ellora.
The distance covered by A is x Km and by B is (28 - x) km.
This is covered in 1 hrs so the speed for :
A = x km/h
B = (28 - x) km / h
A has (28 - x) km to cover whereas B has x km more to cover.
Since we have the distance and the speeds for the two, we can get the time taken to reach respective destinations.
A : (28 - x) / x
B : x /(28 - x)
We know that A arrives 35 minutes later which is equivalent to 7 / 12 hrs
Putting this in an equation form we have :
x / (28 - x) + 7/12 = (28 - x) / x
Expanding the equation we get :
12 x^2 + 196 x - 7x^2 = 9408 - 672x + 12x^2
Collecting like terms together :
- 7x^2 + 868 x - 9408 = 0
Dividing through by a negative :
7x^2 - 868 x + 9408 = 0
Solving for X using the quadratic formula we have :
X = {868 +/-√(868x - 4 x7 x 9408)} / (2 x 7)
X = {868 +/- (700)} / 14
X = 12 or 112
We pick 12 since 112 is more than the total distance thus it is unrealistic.
Speed of B is : (28 - 12) = 16
16 m / s