NEET Exam > NEET Questions > 2 L of an ideal gas at a pressure of 10 atm e...
Start Learning for Free
2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?
- a)8 L-atm
- b)16 1 L-atm
- c)24.0 L-atm
- d)No work is done
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
2 L of an ideal gas at a pressure of 10 atm expands isothermally into ...
Free Test
FREE
| Start Free Test |
Community Answer
2 L of an ideal gas at a pressure of 10 atm expands isothermally into ...
Given information:
Initial volume (V1) = 2 L
Initial pressure (P1) = 10 atm
Final volume (V2) = 10 L
Final pressure (P2) = 0 atm (vacuum)
The process is isothermal, which means the temperature remains constant during the expansion.
To calculate the work done in the expansion, we can use the formula:
Work done (W) = -nRT ln(V2/V1)
where:
n = number of moles of gas
R = ideal gas constant
T = temperature in Kelvin
First, we need to find the number of moles of gas using the ideal gas equation:
PV = nRT
Rearranging the equation, we have:
n = PV/RT
Since the temperature remains constant, we can use the initial temperature (T1) to calculate the number of moles.
Next, we can substitute the values into the work done formula:
W = -nRT ln(V2/V1)
Let's calculate step by step:
1. Calculate the number of moles:
n = (P1 * V1) / (R * T1)
2. Calculate the work done:
W = -nRT ln(V2/V1)
Substituting the values:
W = -[(P1 * V1) / (R * T1)] * R * T1 * ln(V2/V1)
= -P1 * V1 ln(V2/V1)
Now, let's plug in the given values:
W = -10 atm * 2 L ln(10 L/2 L)
= -10 atm * 2 L ln(5)
= -10 atm * 2 L * 1.6094
= -32.188 L-atm
Since work is a form of energy, it cannot have a negative value. Therefore, we take the magnitude of the work done:
|W| = 32.188 L-atm
So, the correct answer is option 'A': 8 L-atm.
Initial volume (V1) = 2 L
Initial pressure (P1) = 10 atm
Final volume (V2) = 10 L
Final pressure (P2) = 0 atm (vacuum)
The process is isothermal, which means the temperature remains constant during the expansion.
To calculate the work done in the expansion, we can use the formula:
Work done (W) = -nRT ln(V2/V1)
where:
n = number of moles of gas
R = ideal gas constant
T = temperature in Kelvin
First, we need to find the number of moles of gas using the ideal gas equation:
PV = nRT
Rearranging the equation, we have:
n = PV/RT
Since the temperature remains constant, we can use the initial temperature (T1) to calculate the number of moles.
Next, we can substitute the values into the work done formula:
W = -nRT ln(V2/V1)
Let's calculate step by step:
1. Calculate the number of moles:
n = (P1 * V1) / (R * T1)
2. Calculate the work done:
W = -nRT ln(V2/V1)
Substituting the values:
W = -[(P1 * V1) / (R * T1)] * R * T1 * ln(V2/V1)
= -P1 * V1 ln(V2/V1)
Now, let's plug in the given values:
W = -10 atm * 2 L ln(10 L/2 L)
= -10 atm * 2 L ln(5)
= -10 atm * 2 L * 1.6094
= -32.188 L-atm
Since work is a form of energy, it cannot have a negative value. Therefore, we take the magnitude of the work done:
|W| = 32.188 L-atm
So, the correct answer is option 'A': 8 L-atm.
|
Explore Courses for NEET exam
|
|
Top Courses for NEETView all
Question Description
2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?a)8 L-atmb)16 1 L-atmc)24.0 L-atmd)No work is doneCorrect answer is option 'A'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?a)8 L-atmb)16 1 L-atmc)24.0 L-atmd)No work is doneCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?a)8 L-atmb)16 1 L-atmc)24.0 L-atmd)No work is doneCorrect answer is option 'A'. Can you explain this answer?.
2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?a)8 L-atmb)16 1 L-atmc)24.0 L-atmd)No work is doneCorrect answer is option 'A'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?a)8 L-atmb)16 1 L-atmc)24.0 L-atmd)No work is doneCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?a)8 L-atmb)16 1 L-atmc)24.0 L-atmd)No work is doneCorrect answer is option 'A'. Can you explain this answer?.
Solutions for 2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?a)8 L-atmb)16 1 L-atmc)24.0 L-atmd)No work is doneCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of 2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?a)8 L-atmb)16 1 L-atmc)24.0 L-atmd)No work is doneCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?a)8 L-atmb)16 1 L-atmc)24.0 L-atmd)No work is doneCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for 2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?a)8 L-atmb)16 1 L-atmc)24.0 L-atmd)No work is doneCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of 2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?a)8 L-atmb)16 1 L-atmc)24.0 L-atmd)No work is doneCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice 2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?a)8 L-atmb)16 1 L-atmc)24.0 L-atmd)No work is doneCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup