An object 0.5m high is placed at a distance of 0.5m from a concave mir...
Calculation of image position and size for an object placed at a distance of 0.5m from a concave mirror of radius of curvature 0.2m
Gathering given information
- Height of object (ho) = 0.5m
- Distance of object from mirror (u) = -0.5m (negative sign indicates that the object is placed on the left side of the mirror)
- Radius of curvature (R) = -0.2m (negative sign indicates that it is a concave mirror)
Calculation of image distance (v)
Using mirror formula:
1/f = 1/v - 1/u
Where f is the focal length of the mirror
As the mirror is concave, the focal length is given by:
f = R/2 = -0.1m
Substituting the values, we get:
1/-0.1 = 1/v + 1/-0.5
On solving this equation, we get:
v = -0.1667m
Calculation of magnification (m)
Magnification is given by:
m = -v/u
Substituting the values, we get:
m = -(-0.1667)/(-0.5)
m = 0.3333
Calculation of image height (hi)
Image height is given by:
hi = m * ho
Substituting the values, we get:
hi = 0.3333 * 0.5
hi = 0.1667m
Conclusion
Thus, the image is formed at a distance of -0.1667m from the mirror and is 0.1667m high. The negative sign indicates that the image is formed on the same side of the mirror as the object and is inverted.