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Consider the function f(x) = √x and g(x)=7x+b.In the standard (X,y) coordinate plane y=f(g(x)) passes through (4,6) ?what is the value of b?
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Consider the function f(x) = √x and g(x)=7x+b.In the standard (X,y) co...
For nested functions like f(g(x)), we must work from inside out. So we start with the function g(x) as the input value for function f(x).
Given: g(x) = 7x + b, and f(x) = sqrt(x).
So, we get, f(g(x)) = sqrt(7x + b).
We are also given that y = f(g(x)) function passes through coordinates (4,6), so let us use the value at this coordinate in the above function. Here x = 4, and y = 6. We get:
6 = sqrt(7 x 4 + b)
We can square both sides to eliminate the square root. We get:
36 = 28 + b
Or, 36 - 28 = 
Or, b = 8
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Consider the function f(x) = √x and g(x)=7x+b.In the standard (X,y) co...
Explanation:

Given:
- f(x) = √x
- g(x) = 7x + b
- y = f(g(x))
- Point (4,6) lies on y = f(g(x))

Step 1: Find g(x)
Since g(x) = 7x + b, we can substitute this into f(x) to get y = f(7x + b).

Step 2: Find y = f(g(x))
Given that y = f(g(x)), we have y = √(7x + b).

Step 3: Substitute the point (4,6)
Since the point (4,6) lies on y = √(7x + b), we can substitute x=4 and y=6 into the equation to get 6 = √(7(4) + b).

Step 4: Solve for b
Now, we can solve for b:
6 = √(28 + b)
6 = √28 + √b
6 = √28 + √b
6 - √28 = √b
36 - 28 = b
b = 8

Therefore, the value of b is 8.
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Consider the function f(x) = √x and g(x)=7x+b.In the standard (X,y) coordinate plane y=f(g(x)) passes through (4,6) ?what is the value of b?
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