Explanation of the Elimination Method:
The elimination method is a technique used to solve a system of linear equations in two variables. In this method, we eliminate one of the variables by adding or subtracting the equations in such a way that one variable gets canceled out, leaving us with an equation in one variable that can be easily solved.

Given Equations:
- s - t = 3
- 3s/3 + t/2 = 6

Step 1: Simplify the Equations
- From the second equation, we can simplify it as s + t/2 = 6
- Now we have the following equations to work with:
- s - t = 3
- s + t/2 = 6

Step 2: Eliminate a Variable
- To eliminate the variable t, we can add the two equations together:
(s - t) + (s + t/2) = 3 + 6
- This simplifies to:
2s + t/2 = 9

Step 3: Solve for the Remaining Variable
- Now we have the equation 2s + t/2 = 9
- We can multiply the whole equation by 2 to get rid of the fraction:
4s + t = 18
- We can substitute the value of t from the first equation into this equation to find the value of s.

Step 4: Find the Values of s and t
- From the first equation, we have s - t = 3
- Substituting t = s - 3 into the equation 4s + t = 18, we get:
4s + s - 3 = 18
5s - 3 = 18
5s = 21
s = 21/5
- Now that we have the value of s, we can substitute it back into the first equation to find t:
s - t = 3
21/5 - t = 3
t = 21/5 - 3
t = 21/5 - 15/5
t = 6/5

Step 5: Final Solution
- The solution to the system of equations is:
s = 21/5
t = 6/5
Therefore, the values of s and t that satisfy both equations are s = 21/5 and t = 6/5.

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