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Find the force between two charges when they are brought in contact and separated by 4cm apart, charges are 2nC and -1nC, in μN.
- a)1.44
- b)2.44
- c)1.404
- d)2.404
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Find the force between two charges when they are brought in contact an...
Answer: c
Explanation: Before the charges are brought into contact, F = 11.234 μN.
After charges are brought into contact and then separated, charge on each sphere is, (q1 + q2)/2 = 0.5nC
On calculating the force with q1 = q2 = 0.5nC, F = 1.404μN.
Explanation: Before the charges are brought into contact, F = 11.234 μN.
After charges are brought into contact and then separated, charge on each sphere is, (q1 + q2)/2 = 0.5nC
On calculating the force with q1 = q2 = 0.5nC, F = 1.404μN.
Most Upvoted Answer
Find the force between two charges when they are brought in contact an...
Order to find the force between two charges when they are brought in contact and separated by 4 cm apart, we need to calculate the electric force using Coulomb's Law. Coulomb's Law states that the electric force (F) between two charges (q1 and q2) is given by the equation:
F = (k * q1 * q2) / r^2
Where:
- F is the electric force between the charges,
- k is the electrostatic constant (k = 9 x 10^9 Nm^2/C^2),
- q1 and q2 are the charges, and
- r is the distance between the charges.
In this case, the charges are 2 nC (nanoCoulombs) and -1 nC, and the distance between them is 4 cm (0.04 m).
Let's calculate the force:
F = (9 x 10^9 Nm^2/C^2) * (2 x 10^-9 C) * (-1 x 10^-9 C) / (0.04 m)^2
Simplifying the equation:
F = (9 x 2 x -1) / (0.04^2) * (10^9 C^2/Nm^2)
F = (-18) / 0.0016 * (10^9 C^2/Nm^2)
F = -11.25 x 10^9 N
Therefore, the force between the charges is -11.25 x 10^9 Newtons. The negative sign indicates that the force is attractive.
F = (k * q1 * q2) / r^2
Where:
- F is the electric force between the charges,
- k is the electrostatic constant (k = 9 x 10^9 Nm^2/C^2),
- q1 and q2 are the charges, and
- r is the distance between the charges.
In this case, the charges are 2 nC (nanoCoulombs) and -1 nC, and the distance between them is 4 cm (0.04 m).
Let's calculate the force:
F = (9 x 10^9 Nm^2/C^2) * (2 x 10^-9 C) * (-1 x 10^-9 C) / (0.04 m)^2
Simplifying the equation:
F = (9 x 2 x -1) / (0.04^2) * (10^9 C^2/Nm^2)
F = (-18) / 0.0016 * (10^9 C^2/Nm^2)
F = -11.25 x 10^9 N
Therefore, the force between the charges is -11.25 x 10^9 Newtons. The negative sign indicates that the force is attractive.
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