The mean of the first 10 multiples of 6 isa)3.3b)33c)34d)none of these...
We have first ten multiples of 6 as follows:
6,12,18,24,30,36,42,48,54,60
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The mean of the first 10 multiples of 6 isa)3.3b)33c)34d)none of these...
Mean of First 10 Multiples of 6
To find the mean of the first 10 multiples of 6, we need to add the first 10 multiples of 6 and divide by 10.
Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60
Addition: 6 + 12 + 18 + 24 + 30 + 36 + 42 + 48 + 54 + 60 = 330
Mean: 330/10 = 33
Therefore, the correct answer is option B, 33.
The mean of the first 10 multiples of 6 isa)3.3b)33c)34d)none of these...
First ten multiple of 6 are
6,12,18,24,30,36,42,48,54,60
mean =sum of all observations/total no of observations
=330/10
=33
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