If a and b are the the solution of x²+ mx +m=0 then find the value of ...
If a and b are the the solution of x²+ mx +m=0 then find the value of ...
**Solution**
To find the value of \(a^3 b^3\), we need to determine the values of \(a\) and \(b\) first.
Given that \(a\) and \(b\) are the solutions of the quadratic equation \(x^2 - mx + m = 0\), we can use the quadratic formula to find their values.
**Finding the Solutions**
The quadratic formula states that for any quadratic equation of the form \(ax^2 + bx + c = 0\), the solutions can be found using the formula:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
In this case, the equation is \(x^2 - mx + m = 0\), so \(a = 1\), \(b = -m\), and \(c = m\). Substituting these values into the formula, we have:
\[x = \frac{-(-m) \pm \sqrt{(-m)^2 - 4(1)(m)}}{2(1)}\]
Simplifying further:
\[x = \frac{m \pm \sqrt{m^2 - 4m}}{2}\]
**Determining the Values of a and b**
Since \(a\) and \(b\) are the solutions of the quadratic equation, we can equate the quadratic formula to \(a\) and \(b\) respectively:
\[a = \frac{m + \sqrt{m^2 - 4m}}{2}\]
\[b = \frac{m - \sqrt{m^2 - 4m}}{2}\]
**Calculating a³ and b³**
To find the values of \(a^3\) and \(b^3\), we can cube the equations for \(a\) and \(b\) respectively:
\[a^3 = \left(\frac{m + \sqrt{m^2 - 4m}}{2}\right)^3\]
\[b^3 = \left(\frac{m - \sqrt{m^2 - 4m}}{2}\right)^3\]
Simplifying these expressions, we have:
\[a^3 = \frac{(m + \sqrt{m^2 - 4m})^3}{8}\]
\[b^3 = \frac{(m - \sqrt{m^2 - 4m})^3}{8}\]
**Calculating a³ b³**
Finally, we can find the value of \(a^3 b^3\) by multiplying \(a^3\) and \(b^3\):
\[a^3 b^3 = \frac{(m + \sqrt{m^2 - 4m})^3}{8} \times \frac{(m - \sqrt{m^2 - 4m})^3}{8}\]
Simplifying further, we have:
\[a^3 b^3 = \frac{(m + \sqrt{m^2 - 4m})(m - \sqrt{m^2 - 4m})^3}{64}\]
This expression represents the value of \(a^3 b^3\) in terms of \(m\).
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