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The sum of first q term of an AP is 162 .the ratio of its 6th term to its 13th term is 1:2. Find the first and 15th term of an AP
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The sum of first q term of an AP is 162 .the ratio of its 6th term to ...
Hiiii

there is a mistake 9 will be come not q..

Given,

Sum of 9 terms= 162

Ratio of 6th term and 13th term= 1:2

Formula is an= a1+(n-1)d

Then the sixth term a6= a1+5d

The 13th term is a13=a1+12d

As given a6/a13 is 1/2

(a1+5d)/(a1+12d)=1/2

After cross multiplication

2(a1+5d)=1(a1+12d)

2a1+10d=a1+12d

2a1-a1=12d-10d

Therefore the first term a1=2d
Sn=(n/2)[2a+(n-1)d]
S9=(9/2)[2(2d)+(9-1)d]
S9=(9/2)(4d+8d)
162=(9/2)(12d)
162=9(6d)
54d=162
d=3........ (1)

a1=2d=2(3)=6

a15=6+(15-1)3=6+3(14)=48

The first term of A.P is 6
The 15th term of A.P is 48

Hope it's help
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The sum of first q term of an AP is 162 .the ratio of its 6th term to its 13th term is 1:2. Find the first and 15th term of an AP?
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