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The ratio of the dimension of Planck’s constant and that of the moment of inertia is the dimension of [2005]
- a)time
- b)frequency
- c)angular momentum
- d)velocity
Correct answer is option 'B'. Can you explain this answer?
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The ratio of the dimension of Planck’s constant and that of the ...
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The ratio of the dimension of Planck’s constant and that of the ...
The Planck length is approximately 1.616229 x 10^-35 meters, and the Planck time is approximately 5.39116 x 10^-44 seconds.
The ratio of the Planck length to the Planck time can be calculated as:
(1.616229 x 10^-35 m) / (5.39116 x 10^-44 s) = 2.998 x 10^8 m/s
This ratio represents the speed of light in a vacuum, which is a fundamental constant in physics.
The ratio of the Planck length to the Planck time can be calculated as:
(1.616229 x 10^-35 m) / (5.39116 x 10^-44 s) = 2.998 x 10^8 m/s
This ratio represents the speed of light in a vacuum, which is a fundamental constant in physics.
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The ratio of the dimension of Planck’s constant and that of the ...
We know that E= hv(v is frequency)
h is plank's constant.
so h=Energy/frequency
dimension of energy is M1L2T-2
and for frequency=1/T
SO h=M1L2T-1
now moment of inertia (I) =mr×r
so dimension of I=M1L2
Now divide h/I=M1L2T-1/M1L2
h/l =T-1
=1/T
1/T is the unit of frequency.
so the answer is B.
Hope it helps.
h is plank's constant.
so h=Energy/frequency
dimension of energy is M1L2T-2
and for frequency=1/T
SO h=M1L2T-1
now moment of inertia (I) =mr×r
so dimension of I=M1L2
Now divide h/I=M1L2T-1/M1L2
h/l =T-1
=1/T
1/T is the unit of frequency.
so the answer is B.
Hope it helps.
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The ratio of the dimension of Planck’s constant and that of the moment of inertia is the dimension of [2005]a)timeb)frequencyc)angular momentumd)velocityCorrect answer is option 'B'. Can you explain this answer?
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