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A buffer solution PH (9.26) is made by dissolving x-mole of ammonium sulphate and 0.1 mole of ammonia into 100 ml solution. If PKb of ammonia is 4.74, calculate the mole(s) of ammonium sulphate (rounded up to first decimal place):
Correct answer is '0.05'. Can you explain this answer?
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A buffer solution PH (9.26) is made by dissolving x-mole of ammonium s...
Given Information:
- pH of buffer solution = 9.26
- Amount of ammonia = 0.1 mole
- PKb of ammonia = 4.74
- Volume of solution = 100 mL
To find:
- Moles of ammonium sulphate required
Solution:
1. Write the balanced chemical equation for ammonium sulphate and ammonia dissociation in water:
(NH4)2SO4 → 2NH4+ + SO42-
NH3 + H2O ⇌ NH4+ + OH-
2. Calculate the concentration of ammonia and ammonium ions in the buffer solution using the Henderson-Hasselbalch equation:
pH = pKa + log([A-]/[HA])
where Ka = Kw/Kb
- Kw = 1 x 10^-14 (at 25°C)
- pKa = 14 - pKb = 9.26 (given)
- [A-] = [NH3] = 0.1 mole / 0.1 L = 1 M
- [HA] = [NH4+] = x mole / 0.1 L
9.26 = 9.74 + log([1]/[x])
log([1]/[x]) = -0.48
[1]/[x] = 0.29
x = 1/[0.29] = 3.45 ≈ 0.05 (rounded up to first decimal place)
3. Therefore, the moles of ammonium sulphate required to make the buffer solution with a pH of 9.26 is 0.05.
- pH of buffer solution = 9.26
- Amount of ammonia = 0.1 mole
- PKb of ammonia = 4.74
- Volume of solution = 100 mL
To find:
- Moles of ammonium sulphate required
Solution:
1. Write the balanced chemical equation for ammonium sulphate and ammonia dissociation in water:
(NH4)2SO4 → 2NH4+ + SO42-
NH3 + H2O ⇌ NH4+ + OH-
2. Calculate the concentration of ammonia and ammonium ions in the buffer solution using the Henderson-Hasselbalch equation:
pH = pKa + log([A-]/[HA])
where Ka = Kw/Kb
- Kw = 1 x 10^-14 (at 25°C)
- pKa = 14 - pKb = 9.26 (given)
- [A-] = [NH3] = 0.1 mole / 0.1 L = 1 M
- [HA] = [NH4+] = x mole / 0.1 L
9.26 = 9.74 + log([1]/[x])
log([1]/[x]) = -0.48
[1]/[x] = 0.29
x = 1/[0.29] = 3.45 ≈ 0.05 (rounded up to first decimal place)
3. Therefore, the moles of ammonium sulphate required to make the buffer solution with a pH of 9.26 is 0.05.
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A buffer solution PH (9.26) is made by dissolving x-mole of ammonium sulphate and 0.1 mole of ammonia into 100 ml solution. If PKb of ammonia is 4.74, calculate the mole(s) of ammonium sulphate (rounded up to first decimal place):Correct answer is '0.05'. Can you explain this answer?
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A buffer solution PH (9.26) is made by dissolving x-mole of ammonium sulphate and 0.1 mole of ammonia into 100 ml solution. If PKb of ammonia is 4.74, calculate the mole(s) of ammonium sulphate (rounded up to first decimal place):Correct answer is '0.05'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A buffer solution PH (9.26) is made by dissolving x-mole of ammonium sulphate and 0.1 mole of ammonia into 100 ml solution. If PKb of ammonia is 4.74, calculate the mole(s) of ammonium sulphate (rounded up to first decimal place):Correct answer is '0.05'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A buffer solution PH (9.26) is made by dissolving x-mole of ammonium sulphate and 0.1 mole of ammonia into 100 ml solution. If PKb of ammonia is 4.74, calculate the mole(s) of ammonium sulphate (rounded up to first decimal place):Correct answer is '0.05'. Can you explain this answer?.
A buffer solution PH (9.26) is made by dissolving x-mole of ammonium sulphate and 0.1 mole of ammonia into 100 ml solution. If PKb of ammonia is 4.74, calculate the mole(s) of ammonium sulphate (rounded up to first decimal place):Correct answer is '0.05'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A buffer solution PH (9.26) is made by dissolving x-mole of ammonium sulphate and 0.1 mole of ammonia into 100 ml solution. If PKb of ammonia is 4.74, calculate the mole(s) of ammonium sulphate (rounded up to first decimal place):Correct answer is '0.05'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A buffer solution PH (9.26) is made by dissolving x-mole of ammonium sulphate and 0.1 mole of ammonia into 100 ml solution. If PKb of ammonia is 4.74, calculate the mole(s) of ammonium sulphate (rounded up to first decimal place):Correct answer is '0.05'. Can you explain this answer?.
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A buffer solution PH (9.26) is made by dissolving x-mole of ammonium sulphate and 0.1 mole of ammonia into 100 ml solution. If PKb of ammonia is 4.74, calculate the mole(s) of ammonium sulphate (rounded up to first decimal place):Correct answer is '0.05'. Can you explain this answer?, a detailed solution for A buffer solution PH (9.26) is made by dissolving x-mole of ammonium sulphate and 0.1 mole of ammonia into 100 ml solution. If PKb of ammonia is 4.74, calculate the mole(s) of ammonium sulphate (rounded up to first decimal place):Correct answer is '0.05'. Can you explain this answer? has been provided alongside types of A buffer solution PH (9.26) is made by dissolving x-mole of ammonium sulphate and 0.1 mole of ammonia into 100 ml solution. If PKb of ammonia is 4.74, calculate the mole(s) of ammonium sulphate (rounded up to first decimal place):Correct answer is '0.05'. Can you explain this answer? theory, EduRev gives you an
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