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If such numbers which are divisible by 5, and also those which have 5 as one of the digits are eliminated from the numbers 1 to 60, how many numbers would remain?
  • a)
    53
  • b)
    47
  • c)
      40
  • d)
    42
Correct answer is option 'C'. Can you explain this answer?
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If such numbers which are divisible by 5, and also those which have 5 ...
Eliminating Numbers Divisible by 5 and Those with 5 as a Digit

To find the number of remaining numbers between 1 and 60 after eliminating those that are divisible by 5 and those that have 5 as one of their digits, follow the steps below:

Step 1: List the Numbers between 1 and 60

List all the numbers between 1 and 60 in ascending order, as shown below:

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60

Step 2: Eliminate Numbers Divisible by 5

Eliminate all the numbers that are divisible by 5 from the list. They are:

5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60

The remaining numbers are:

1, 2, 3, 4, 6, 7, 8, 9, 11, 12, 13, 14, 16, 17, 18, 19, 21, 22, 23, 24, 26, 27, 28, 29, 31, 32, 33, 34, 36, 37, 38, 39, 41, 42, 43, 44, 46, 47, 48, 49, 51, 52, 53, 54, 56, 57, 58, 59

Step 3: Eliminate Numbers with 5 as a Digit

Eliminate all the numbers that have 5 as one of their digits from the list. They are:

5, 15, 25, 35, 45, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59

The remaining numbers are:

1, 2, 3, 4, 6, 7, 8, 9, 11, 12, 13, 14, 16, 17, 18, 19, 21, 22, 23, 24, 26, 27, 28, 29, 31, 32, 33, 34, 36, 37, 38, 39, 41, 42, 43, 44, 46, 47, 48, 49

Step 4: Count the Remaining Numbers

Count the remaining numbers from the list
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