**Telophase I in Meiosis**

Telophase I is the final stage of the first meiotic division (meiosis I). During this stage, several important events take place that ultimately lead to the formation of two haploid daughter cells.

**Nuclear Membrane and Nucleolus Disappear**

In telophase I, the nuclear membrane and nucleolus disappear. This is a significant event that occurs as part of the overall process of cell division.

**Explanation**

Telophase I is preceded by anaphase I, during which homologous chromosomes separate and move towards opposite poles of the cell. In telophase I, these separated homologous chromosomes reach the opposite poles and ultimately give rise to two distinct nuclei.

**Reoccurrence of Nuclear Membrane and Nucleolus**

After the separation of homologous chromosomes in anaphase I, the nuclear membrane and nucleolus disintegrate or disappear. However, in telophase I, as the chromosomes reach their respective poles, a new nuclear membrane and nucleolus start to re-form around each set of chromosomes.

This reoccurrence of the nuclear membrane and nucleolus is essential because it helps in the organization and protection of genetic material within the newly formed nuclei. The nuclear membrane acts as a barrier, separating the genetic material from the cytoplasm and other cellular components. The nucleolus, on the other hand, plays a crucial role in the synthesis of ribosomes.

**Conclusion**

In conclusion, during telophase I of meiosis, the nuclear membrane and nucleolus disappear initially as the homologous chromosomes separate. However, as the chromosomes reach their respective poles, the nuclear membrane and nucleolus re-form around each set of chromosomes. This reoccurrence is important for the organization and protection of genetic material in the newly formed nuclei. Therefore, the correct answer is option D, "Reoccurrence of nuclear membrane and nucleolus."