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Sin^6 - cos^6 evaluate the value?
Verified Answer
Sin^6 - cos^6 evaluate the value?
sin^6∅ - cos^6∅
= (sin^2∅)^3 - (cos^2∅)^3
use the formula,
a^3 - b^3 = (a - b)(a^2 + b^2 + ab )

= (sin^2∅ - cos^2∅)(sin⁴∅+ cos⁴∅+ sin^2∅.cos^2∅)
= -(cos^2∅- sin^2∅){(sin^2∅ + cos^2∅)^2 - 2sin^2∅.cos^2∅ + sin^2∅.cos^2∅}
= - cos2∅.{ 1 - 1/4(2sin∅.cos∅)^2}
= -cos2∅(4 - sin^2 (2∅))/4

[ use, cos^2 x - sin^2 x = cos2x , 2sinx.cosx = sin2x ]
This question is part of UPSC exam. View all Class 10 courses
Most Upvoted Answer
Sin^6 - cos^6 evaluate the value?
Expression:
The given expression is sin^6 - cos^6.

Solution:
To evaluate the given expression sin^6 - cos^6, we can use the trigonometric identity:

sin^2θ - cos^2θ = 1

We can rewrite the expression as:

sin^6 - cos^6 = (sin^2)^3 - (cos^2)^3

Using the identity sin^2θ - cos^2θ = 1, we can substitute:

(sin^2)^3 - (cos^2)^3 = (1 - cos^2)^3 - (cos^2)^3

Step 1: Expand the expression:

(1 - cos^2)^3 - (cos^2)^3 = (1 - 3cos^2 + 3cos^4 - cos^6) - (cos^6)

Simplifying further:

= 1 - 3cos^2 + 3cos^4 - cos^6 - cos^6

Step 2: Combine like terms:

= 1 - 3cos^2 - 2cos^6 + 3cos^4

Step 3: Rearrange the terms:

= 1 - 2cos^6 - 3cos^2 + 3cos^4

Step 4: Factor out the common terms:

= 1 - cos^2(2cos^4 + 3 - 3cos^2)

Step 5: Simplify the expression inside the parentheses:

= 1 - cos^2(2cos^4 - 3cos^2 + 3)

Step 6: Evaluate the expression inside the parentheses:

Let's substitute x = cos^2:

= 1 - x(2x^2 - 3x + 3)

Step 7: Simplify the expression inside the parentheses:

= 1 - 2x^3 + 3x^2 - 3x

Step 8: Substitute back cos^2 for x:

= 1 - 2(cos^2)^3 + 3(cos^2)^2 - 3(cos^2)

Step 9: Simplify further:

= 1 - 2cos^6 + 3cos^4 - 3cos^2

Therefore, the value of sin^6 - cos^6 is 1 - 2cos^6 + 3cos^4 - 3cos^2.
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Sin^6 - cos^6 evaluate the value?
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