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A household uses the following electric appliances: (i) Refrigerator of rating 400 W for 10 h each day. (ii) Two electric fans of rating 80 W each for 6 h daily. (iii) Six electric tubes of rating 18 W each for 6 h daily. Calculate the electricity bill for the household for month of June if cost of electrical energy is 3 per unit.?
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A household uses the following electric appliances: (i) Refrigerator o...
I) Energy consumed by refrigerator of rating 400 W for ten hours each day,
ii) Energy consumed by two electric fans of rating 80 W each for twelve hours each day is,
iii) Energy consumed by six electric tubes of rating 18 W each for 6 hours each day is,
ii) Energy consumed by two electric fans of rating 80 W each for twelve hours each day is,
iii) Energy consumed by six electric tubes of rating 18 W each for 6 hours each day is,
Total energy consumed in the month of June (30 days) is given by,
= (0.8 + 1.92 + 0.648) x 30 kWh
= 6.568 x 30
= 197.04 kWh
Electricity bill for the month of June = Rs 197.04 x 3
= Rs 591.12
= Rs 591 (approx.)
This question is part of UPSC exam. View all Class 10 courses
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A household uses the following electric appliances: (i) Refrigerator o...
Calculation of Electricity Bill for the household for the month of June
To calculate the electricity bill for the household, we need to determine the energy consumption of each appliance and then calculate the total energy consumed. Finally, we can multiply the total energy consumed by the cost of electrical energy to get the electricity bill for the month of June.
Determining the energy consumption of each appliance:
1. Refrigerator:
- Rating: 400 W
- Daily usage: 10 hours
- Energy consumption per day: 400 W * 10 h = 4000 Wh = 4 kWh
2. Electric fans:
- Rating: 80 W each (2 fans in total)
- Daily usage: 6 hours
- Energy consumption per fan per day: 80 W * 6 h = 480 Wh = 0.48 kWh
- Energy consumption for both fans per day: 0.48 kWh * 2 = 0.96 kWh
3. Electric tubes:
- Rating: 18 W each (6 tubes in total)
- Daily usage: 6 hours
- Energy consumption per tube per day: 18 W * 6 h = 108 Wh = 0.108 kWh
- Energy consumption for all tubes per day: 0.108 kWh * 6 = 0.648 kWh
Calculating the total energy consumed:
Total energy consumed per day = Energy consumption of refrigerator + Energy consumption of fans + Energy consumption of tubes
= 4 kWh + 0.96 kWh + 0.648 kWh
= 5.608 kWh
Total energy consumed for the month of June = Total energy consumed per day * Number of days in June
= 5.608 kWh * 30 days
= 168.24 kWh
Calculating the electricity bill:
Electricity bill = Total energy consumed * Cost of electrical energy per unit
= 168.24 kWh * $3
= $504.72
Therefore, the electricity bill for the household for the month of June is $504.72.
To calculate the electricity bill for the household, we need to determine the energy consumption of each appliance and then calculate the total energy consumed. Finally, we can multiply the total energy consumed by the cost of electrical energy to get the electricity bill for the month of June.
Determining the energy consumption of each appliance:
1. Refrigerator:
- Rating: 400 W
- Daily usage: 10 hours
- Energy consumption per day: 400 W * 10 h = 4000 Wh = 4 kWh
2. Electric fans:
- Rating: 80 W each (2 fans in total)
- Daily usage: 6 hours
- Energy consumption per fan per day: 80 W * 6 h = 480 Wh = 0.48 kWh
- Energy consumption for both fans per day: 0.48 kWh * 2 = 0.96 kWh
3. Electric tubes:
- Rating: 18 W each (6 tubes in total)
- Daily usage: 6 hours
- Energy consumption per tube per day: 18 W * 6 h = 108 Wh = 0.108 kWh
- Energy consumption for all tubes per day: 0.108 kWh * 6 = 0.648 kWh
Calculating the total energy consumed:
Total energy consumed per day = Energy consumption of refrigerator + Energy consumption of fans + Energy consumption of tubes
= 4 kWh + 0.96 kWh + 0.648 kWh
= 5.608 kWh
Total energy consumed for the month of June = Total energy consumed per day * Number of days in June
= 5.608 kWh * 30 days
= 168.24 kWh
Calculating the electricity bill:
Electricity bill = Total energy consumed * Cost of electrical energy per unit
= 168.24 kWh * $3
= $504.72
Therefore, the electricity bill for the household for the month of June is $504.72.
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A household uses the following electric appliances: (i) Refrigerator of rating 400 W for 10 h each day. (ii) Two electric fans of rating 80 W each for 6 h daily. (iii) Six electric tubes of rating 18 W each for 6 h daily. Calculate the electricity bill for the household for month of June if cost of electrical energy is 3 per unit.?
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A household uses the following electric appliances: (i) Refrigerator of rating 400 W for 10 h each day. (ii) Two electric fans of rating 80 W each for 6 h daily. (iii) Six electric tubes of rating 18 W each for 6 h daily. Calculate the electricity bill for the household for month of June if cost of electrical energy is 3 per unit.? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A household uses the following electric appliances: (i) Refrigerator of rating 400 W for 10 h each day. (ii) Two electric fans of rating 80 W each for 6 h daily. (iii) Six electric tubes of rating 18 W each for 6 h daily. Calculate the electricity bill for the household for month of June if cost of electrical energy is 3 per unit.? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A household uses the following electric appliances: (i) Refrigerator of rating 400 W for 10 h each day. (ii) Two electric fans of rating 80 W each for 6 h daily. (iii) Six electric tubes of rating 18 W each for 6 h daily. Calculate the electricity bill for the household for month of June if cost of electrical energy is 3 per unit.?.
A household uses the following electric appliances: (i) Refrigerator of rating 400 W for 10 h each day. (ii) Two electric fans of rating 80 W each for 6 h daily. (iii) Six electric tubes of rating 18 W each for 6 h daily. Calculate the electricity bill for the household for month of June if cost of electrical energy is 3 per unit.? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A household uses the following electric appliances: (i) Refrigerator of rating 400 W for 10 h each day. (ii) Two electric fans of rating 80 W each for 6 h daily. (iii) Six electric tubes of rating 18 W each for 6 h daily. Calculate the electricity bill for the household for month of June if cost of electrical energy is 3 per unit.? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A household uses the following electric appliances: (i) Refrigerator of rating 400 W for 10 h each day. (ii) Two electric fans of rating 80 W each for 6 h daily. (iii) Six electric tubes of rating 18 W each for 6 h daily. Calculate the electricity bill for the household for month of June if cost of electrical energy is 3 per unit.?.
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A household uses the following electric appliances: (i) Refrigerator of rating 400 W for 10 h each day. (ii) Two electric fans of rating 80 W each for 6 h daily. (iii) Six electric tubes of rating 18 W each for 6 h daily. Calculate the electricity bill for the household for month of June if cost of electrical energy is 3 per unit.?, a detailed solution for A household uses the following electric appliances: (i) Refrigerator of rating 400 W for 10 h each day. (ii) Two electric fans of rating 80 W each for 6 h daily. (iii) Six electric tubes of rating 18 W each for 6 h daily. Calculate the electricity bill for the household for month of June if cost of electrical energy is 3 per unit.? has been provided alongside types of A household uses the following electric appliances: (i) Refrigerator of rating 400 W for 10 h each day. (ii) Two electric fans of rating 80 W each for 6 h daily. (iii) Six electric tubes of rating 18 W each for 6 h daily. Calculate the electricity bill for the household for month of June if cost of electrical energy is 3 per unit.? theory, EduRev gives you an
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