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A small aperture is illuminated with a parallel beam of wavelength=628nm. The emergent beam has an angular divergence of 2degree. The size of aperture is. 1)9×10^-6m. 2)18×10^-6m. 3)27×10^-6m. 4)36×10^-6m?
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A small aperture is illuminated with a parallel beam of wavelength=628...
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A small aperture is illuminated with a parallel beam of wavelength=628...
Given:
- Wavelength of light, λ = 628 nm
- Angular divergence, θ = 2°
To Find:
The size of the aperture
Solution:
The angular divergence can be related to the size of the aperture using the formula:
θ = λ / D
where θ is the angular divergence, λ is the wavelength of light, and D is the size of the aperture.
Step 1: Convert the given wavelength from nm to meters.
λ = 628 nm = 628 × 10^-9 m
Step 2: Convert the given angular divergence from degrees to radians.
θ = 2° = 2 × (π/180) radians
Step 3: Rearrange the formula to solve for the size of the aperture.
D = λ / θ
Step 4: Substitute the values into the formula and calculate.
D = (628 × 10^-9 m) / (2 × (π/180) radians)
D = (628 × 10^-9 m) / (2 × 0.0349 radians)
D ≈ 9.03 × 10^-6 m
Answer:
The size of the aperture is approximately 9 × 10^-6 m.
- Wavelength of light, λ = 628 nm
- Angular divergence, θ = 2°
To Find:
The size of the aperture
Solution:
The angular divergence can be related to the size of the aperture using the formula:
θ = λ / D
where θ is the angular divergence, λ is the wavelength of light, and D is the size of the aperture.
Step 1: Convert the given wavelength from nm to meters.
λ = 628 nm = 628 × 10^-9 m
Step 2: Convert the given angular divergence from degrees to radians.
θ = 2° = 2 × (π/180) radians
Step 3: Rearrange the formula to solve for the size of the aperture.
D = λ / θ
Step 4: Substitute the values into the formula and calculate.
D = (628 × 10^-9 m) / (2 × (π/180) radians)
D = (628 × 10^-9 m) / (2 × 0.0349 radians)
D ≈ 9.03 × 10^-6 m
Answer:
The size of the aperture is approximately 9 × 10^-6 m.
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A small aperture is illuminated with a parallel beam of wavelength=628nm. The emergent beam has an angular divergence of 2degree. The size of aperture is. 1)9×10^-6m. 2)18×10^-6m. 3)27×10^-6m. 4)36×10^-6m?
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A small aperture is illuminated with a parallel beam of wavelength=628nm. The emergent beam has an angular divergence of 2degree. The size of aperture is. 1)9×10^-6m. 2)18×10^-6m. 3)27×10^-6m. 4)36×10^-6m? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A small aperture is illuminated with a parallel beam of wavelength=628nm. The emergent beam has an angular divergence of 2degree. The size of aperture is. 1)9×10^-6m. 2)18×10^-6m. 3)27×10^-6m. 4)36×10^-6m? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A small aperture is illuminated with a parallel beam of wavelength=628nm. The emergent beam has an angular divergence of 2degree. The size of aperture is. 1)9×10^-6m. 2)18×10^-6m. 3)27×10^-6m. 4)36×10^-6m?.
A small aperture is illuminated with a parallel beam of wavelength=628nm. The emergent beam has an angular divergence of 2degree. The size of aperture is. 1)9×10^-6m. 2)18×10^-6m. 3)27×10^-6m. 4)36×10^-6m? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A small aperture is illuminated with a parallel beam of wavelength=628nm. The emergent beam has an angular divergence of 2degree. The size of aperture is. 1)9×10^-6m. 2)18×10^-6m. 3)27×10^-6m. 4)36×10^-6m? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A small aperture is illuminated with a parallel beam of wavelength=628nm. The emergent beam has an angular divergence of 2degree. The size of aperture is. 1)9×10^-6m. 2)18×10^-6m. 3)27×10^-6m. 4)36×10^-6m?.
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