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When a metallic surface is illuminated with radiation of wavelength λ the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2:, the stopping potential is V/4. The threshold wavelength for the metallic surface is :
  • a)
  • b)
  • c)
  • d)
    5/2λ
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
When a metallic surface is illuminated with radiation of wavelength &#...
When a metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V.
Photoelectric equation can be written as,

Now, when the same surface is illuminated with radiation of wavelength 2λ, the stopping potential is V/4. So, photoelectric equation can be written as,

From equations (i) and (ii), we get

When a metallic surface is illuminated with radiation of wavelength λ stopping potential is V.
Photoelectric equation can be written as,

Now, when the same surface is illuminated with radiation of wavelength 2λ, the stopping potential is V/4. So, photoelectric equation can be written as,

From equations (i) and (ii), we get
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When a metallic surface is illuminated with radiation of wavelength λthe stopping potential is V. If thesame surface is illuminated with radiation of wavelength 2:, the stopping potential isV/4. The thresholdwavelength for the metallic surface is :a)3λb)4λc)5λd)5/2λCorrect answer is option 'A'. Can you explain this answer?
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