NEET Exam > NEET Questions > A ball is thrown vertically upward with speed...
Start Learning for Free
A ball is thrown vertically upward with speed 35 m/s . Find the displacement and distance covered by the ball in 4th second of motion.
Most Upvoted Answer
A ball is thrown vertically upward with speed 35 m/s . Find the displa...
Initial Parameters:
Displacement:
s = ut + 0.5gt²
s = 35×4 - 0.5×9.8×4²
s = 140 - 78.4
s = 61.6 m (upward)
Distance:
Distance = Distance up + Distance down
Distance up = ut + 0.5gt²
Distance up = 35×4 - 0.5×9.8×4²
Distance up = 61.6 m (upward)
Using the same formula for the downward motion,
Distance down = ut + 0.5gt²
Distance down = 0 + 0.5×9.8×4²
Distance down = 78.4 m (downward)
Thus, the total distance covered by the ball in the 4th second is:
Distance = Distance up + Distance down
Distance = 61.6 + 78.4
Distance = 140 m
Explanation:
- Initial velocity, u = 35 m/s (upward)
- Acceleration due to gravity, g = 9.8 m/s² (downward)
- Time, t = 4 seconds
Displacement:
- Displacement refers to the distance between the initial and final position of an object.
- When a ball is thrown vertically upward, it reaches its maximum height and then falls back to the ground.
- At the highest point, the velocity of the ball becomes zero.
- Thus, the displacement of the ball in the 4th second can be calculated as:
s = ut + 0.5gt²
s = 35×4 - 0.5×9.8×4²
s = 140 - 78.4
s = 61.6 m (upward)
Distance:
- Distance refers to the total length of the path covered by an object.
- When a ball is thrown vertically upward, it covers a certain distance while going up and the same distance while coming down.
- Thus, the total distance covered by the ball in the 4th second can be calculated as:
Distance = Distance up + Distance down
Distance up = ut + 0.5gt²
Distance up = 35×4 - 0.5×9.8×4²
Distance up = 61.6 m (upward)
Using the same formula for the downward motion,
Distance down = ut + 0.5gt²
Distance down = 0 + 0.5×9.8×4²
Distance down = 78.4 m (downward)
Thus, the total distance covered by the ball in the 4th second is:
Distance = Distance up + Distance down
Distance = 61.6 + 78.4
Distance = 140 m
Explanation:
- The given problem involves the calculation of displacement and distance covered by a ball thrown vertically upward with an initial velocity of 35 m/s in the 4th second of motion.
- The formula for displacement and distance covered by a freely falling object can be used to solve the problem.
- The displacement of the ball can be calculated using the formula s = ut + 0.5gt², where s is the displacement, u is the initial velocity, g is the acceleration due to gravity and t is the time.
- The total distance covered by the ball can be calculated by adding the distance covered during the upward and downward motion of the ball.
- During the upward motion, the ball slows down due to the force of gravity, reaches its maximum height, and then starts falling back to the ground.
- At the highest point, the velocity of the ball becomes zero, and the displacement is equal to the maximum height reached by the ball.
- During the downward motion, the ball accelerates due to the force of gravity and covers the same distance as it covered during the upward motion.
Community Answer
A ball is thrown vertically upward with speed 35 m/s . Find the displa...
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
A ball is thrown vertically upward with speed 35 m/s . Find the displacement and distance covered by the ball in 4th second of motion.
Question Description
A ball is thrown vertically upward with speed 35 m/s . Find the displacement and distance covered by the ball in 4th second of motion. for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball is thrown vertically upward with speed 35 m/s . Find the displacement and distance covered by the ball in 4th second of motion. covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is thrown vertically upward with speed 35 m/s . Find the displacement and distance covered by the ball in 4th second of motion..
A ball is thrown vertically upward with speed 35 m/s . Find the displacement and distance covered by the ball in 4th second of motion. for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball is thrown vertically upward with speed 35 m/s . Find the displacement and distance covered by the ball in 4th second of motion. covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is thrown vertically upward with speed 35 m/s . Find the displacement and distance covered by the ball in 4th second of motion..
Solutions for A ball is thrown vertically upward with speed 35 m/s . Find the displacement and distance covered by the ball in 4th second of motion. in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A ball is thrown vertically upward with speed 35 m/s . Find the displacement and distance covered by the ball in 4th second of motion. defined & explained in the simplest way possible. Besides giving the explanation of
A ball is thrown vertically upward with speed 35 m/s . Find the displacement and distance covered by the ball in 4th second of motion., a detailed solution for A ball is thrown vertically upward with speed 35 m/s . Find the displacement and distance covered by the ball in 4th second of motion. has been provided alongside types of A ball is thrown vertically upward with speed 35 m/s . Find the displacement and distance covered by the ball in 4th second of motion. theory, EduRev gives you an
ample number of questions to practice A ball is thrown vertically upward with speed 35 m/s . Find the displacement and distance covered by the ball in 4th second of motion. tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup