A ball is thrown vertically upward from the ground with speed 40 metre...
Initial conditions:
- Speed of the ball when thrown upward: 40 m/s
- Acceleration due to gravity: 10 m/s^2
Key points:
- The ball is thrown vertically upward and collides with the ground after returning.
- The ball experiences a constant acceleration due to gravity throughout its motion.
Calculation of time taken for the ball to reach maximum height:
- The initial vertical velocity is 40 m/s and acceleration is -10 m/s^2 (as the ball is moving against gravity).
- Using the equation v = u + at, where v is final velocity, u is initial velocity, a is acceleration, and t is time, we can find the time taken for the ball to reach maximum height.
- At maximum height, the final velocity becomes zero.
- Therefore, 0 = 40 - 10t.
- Solving this equation, we get t = 4 seconds.
Calculation of maximum height:
- The equation for displacement is s = ut + 0.5at^2, where s is displacement, u is initial velocity, a is acceleration, and t is time.
- Plugging in the values, we get s = 40 * 4 + 0.5 * (-10) * (4^2).
- Simplifying the equation, we get s = 80 meters.
Calculation of time taken for the ball to return to the ground:
- The time taken for the ball to reach maximum height is 4 seconds.
- Since the ball takes the same amount of time to fall back to the ground, the total time for the ball to collide with the ground is 4 seconds + 4 seconds = 8 seconds.
Calculation of total distance traveled:
- The ball reaches a maximum height of 80 meters and then returns to the ground.
- Therefore, the total distance traveled by the ball is 80 meters + 80 meters = 160 meters.
Summary:
- The ball takes 4 seconds to reach its maximum height, which is 80 meters.
- It then takes another 4 seconds to fall back to the ground, resulting in a total time of 8 seconds.
- The total distance traveled by the ball, including the upward and downward motion, is 160 meters.
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