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There are three pillars X, Y and Z of different heights. Three spiders A, B and C start to climb on these pillars simultaneously. In one chance, A climbs on X by6 cm but slips down 1 cm. B climbs on Y by7 cm but slips down3 cm. C climbs on Z by6.5 cm but slips down2 cm. If each of them requires40 chances to reach the top of the pillars, what is the height of the shortest pillar?
  • a)
    161 cm
  • b)
    163 cm
  • c)
    182 cm
  • d)
    210 cm
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
There are three pillars X, Y and Z of different heights. Three spiders...
 A = 39 × 5 + 1 × 6 = 201 
B = 39 × 4 + 1 × 7 = 163 
C = 39 × 4.5 + 1 × 6.5 = 182 
Hence, the correct option is (b).
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Most Upvoted Answer
There are three pillars X, Y and Z of different heights. Three spiders...
Solution:

Given, A climbs X by 6 cm but slips down 1 cm. So, in one chance A climbs (6-1)=5 cm.
Similarly, B climbs Y by 7 cm but slips down 3 cm. So, in one chance B climbs (7-3)=4 cm.
C climbs Z by 6.5 cm but slips down 2 cm. So, in one chance C climbs (6.5-2)=4.5 cm.

It is given that each of them requires 40 chances to reach the top of the pillars.
So, the height of pillar X can be calculated as follows:
Height of pillar X = 40 × 5 = 200 cm
Similarly, the height of pillar Y = 40 × 4 = 160 cm
and the height of pillar Z = 40 × 4.5 = 180 cm

Therefore, the shortest pillar is Y with a height of 160 cm.
Hence, the correct option is (B) 163 cm.
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There are three pillars X, Y and Z of different heights. Three spiders A, B and C start to climb on these pillars simultaneously. In one chance, A climbs on X by6 cm but slips down 1 cm. B climbs on Y by7 cm but slips down3 cm. C climbs on Z by6.5 cm but slips down2 cm. If each of them requires40 chances to reach the top of the pillars, what is the height of the shortest pillar?a)161 cmb)163 cmc)182 cmd)210 cmCorrect answer is option 'B'. Can you explain this answer?
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