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A coin is tossed successively three times. Find the probability of Getting exactly one head or two heads.
- a)1/4
- b)3/4
- c)1/2
- d)3/8
Correct answer is option 'B'. Can you explain this answer?
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Let's consider the possible outcomes when tossing a coin successively three times. Each toss can result in either a head (H) or a tail (T). So, there are 2^3 = 8 possible outcomes:
HHH, HHT, HTH, HTT, THH, THT, TTH, TTT
To find the probability of getting exactly one head or two heads, we need to count the number of favorable outcomes and divide it by the total number of possible outcomes.
Favorable outcomes:
- Getting exactly one head: HTH, HTT, THH, THT (4 outcomes)
- Getting exactly two heads: HHT, HTH, THH (3 outcomes)
Total number of possible outcomes = 8
Probability of getting exactly one head or two heads = (number of favorable outcomes) / (total number of possible outcomes)
= (4 + 3) / 8
= 7 / 8
Therefore, the correct answer is option 'B': 3/4.
HHH, HHT, HTH, HTT, THH, THT, TTH, TTT
To find the probability of getting exactly one head or two heads, we need to count the number of favorable outcomes and divide it by the total number of possible outcomes.
Favorable outcomes:
- Getting exactly one head: HTH, HTT, THH, THT (4 outcomes)
- Getting exactly two heads: HHT, HTH, THH (3 outcomes)
Total number of possible outcomes = 8
Probability of getting exactly one head or two heads = (number of favorable outcomes) / (total number of possible outcomes)
= (4 + 3) / 8
= 7 / 8
Therefore, the correct answer is option 'B': 3/4.
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