When a wire is folded, its length is effectively halved. As a result, the cross-sectional area of the wire doubles. This change in length and cross-sectional area affects the wire's resistance. This response will explain how to calculate the new resistance of a folded wire.


The formula for resistance is:

Resistance (R) = Voltage (V) / Current (I)

Or

R = V/I

Another formula for resistance is:

R = (ρL) / A

Where:
- R is the resistance
- ρ (rho) is the resistivity of the material
- L is the length of the wire
- A is the cross-sectional area of the wire


To calculate the new resistance of a folded wire, we need to know its initial resistance and the new cross-sectional area.

Let's assume that the initial resistance of the wire is 6 ohms, and its cross-sectional area is A.

When the wire is folded, its length is halved, and its cross-sectional area doubles. Therefore, the new cross-sectional area is 2A.

Using the formula for resistance, we can calculate the new resistance of the wire:

R = (ρL) / A

Initial resistance (R1) = (ρL) / A

New resistance (R2) = (ρL/2) / 2A

R2 = R1/4

Therefore, the new resistance of the wire is 6/4 = 1.5 ohms.


When a wire is folded, its resistance decreases because its length is halved, and its cross-sectional area doubles. The new resistance of the wire can be calculated using the formula for resistance, provided the initial resistance and new cross-sectional area are known.