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A certain body weighs 22.42 gm an d h as a measured volume of 4.7 cc. The possible error in the measurement of mass and volume are 0.01 gm and 0.1 cc. Then maximum error in the den sity will be [1991]
- a)22 %
- b)2 %
- c)0.2 %
- d)0.02 %
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A certain body weighs 22.42 gm an d h as a measured volume of 4.7 cc. ...
D = M/V
=2 %Most Upvoted Answer
A certain body weighs 22.42 gm an d h as a measured volume of 4.7 cc. ...
To find the maximum error in the density, we need to consider the errors in both the mass and the volume measurements.
Given:
Mass = 22.42 gm
Volume = 4.7 cc
Error in mass measurement = 0.01 gm
Error in volume measurement = 0.1 cc
Density is calculated by dividing the mass by the volume:
Density = Mass / Volume
Let's calculate the density using the given values:
Density = 22.42 gm / 4.7 cc = 4.7681 gm/cc (rounded to four decimal places)
Now, let's find the maximum possible error in the density.
1. Maximum error in mass:
The maximum error in mass is given as 0.01 gm. Since the mass is in the numerator of the density equation, the error in mass directly affects the density. Therefore, the maximum error in the density due to mass is also 0.01 gm.
2. Maximum error in volume:
The maximum error in volume is given as 0.1 cc. Since the volume is in the denominator of the density equation, the error in volume inversely affects the density. To find the maximum possible error in the density due to volume, we need to calculate the density using the minimum value of volume and subtract it from the density calculated using the maximum value of volume.
Minimum volume = 4.7 cc - 0.1 cc = 4.6 cc
Maximum density due to volume = 22.42 gm / 4.6 cc = 4.8783 gm/cc (rounded to four decimal places)
Maximum error in density due to volume = Maximum density due to volume - Calculated density = 4.8783 gm/cc - 4.7681 gm/cc = 0.1102 gm/cc (rounded to four decimal places)
3. Maximum error in density:
The maximum error in density is the sum of the maximum errors due to mass and volume.
Maximum error in density = Maximum error in mass + Maximum error in density due to volume = 0.01 gm + 0.1102 gm/cc = 0.1202 gm/cc (rounded to four decimal places)
Finally, let's calculate the percentage error in density:
Percentage error in density = (Maximum error in density / Calculated density) * 100
Percentage error in density = (0.1202 gm/cc / 4.7681 gm/cc) * 100 = 2.52%
Therefore, the maximum error in the density is approximately 2%, which is option B.
Given:
Mass = 22.42 gm
Volume = 4.7 cc
Error in mass measurement = 0.01 gm
Error in volume measurement = 0.1 cc
Density is calculated by dividing the mass by the volume:
Density = Mass / Volume
Let's calculate the density using the given values:
Density = 22.42 gm / 4.7 cc = 4.7681 gm/cc (rounded to four decimal places)
Now, let's find the maximum possible error in the density.
1. Maximum error in mass:
The maximum error in mass is given as 0.01 gm. Since the mass is in the numerator of the density equation, the error in mass directly affects the density. Therefore, the maximum error in the density due to mass is also 0.01 gm.
2. Maximum error in volume:
The maximum error in volume is given as 0.1 cc. Since the volume is in the denominator of the density equation, the error in volume inversely affects the density. To find the maximum possible error in the density due to volume, we need to calculate the density using the minimum value of volume and subtract it from the density calculated using the maximum value of volume.
Minimum volume = 4.7 cc - 0.1 cc = 4.6 cc
Maximum density due to volume = 22.42 gm / 4.6 cc = 4.8783 gm/cc (rounded to four decimal places)
Maximum error in density due to volume = Maximum density due to volume - Calculated density = 4.8783 gm/cc - 4.7681 gm/cc = 0.1102 gm/cc (rounded to four decimal places)
3. Maximum error in density:
The maximum error in density is the sum of the maximum errors due to mass and volume.
Maximum error in density = Maximum error in mass + Maximum error in density due to volume = 0.01 gm + 0.1102 gm/cc = 0.1202 gm/cc (rounded to four decimal places)
Finally, let's calculate the percentage error in density:
Percentage error in density = (Maximum error in density / Calculated density) * 100
Percentage error in density = (0.1202 gm/cc / 4.7681 gm/cc) * 100 = 2.52%
Therefore, the maximum error in the density is approximately 2%, which is option B.
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A certain body weighs 22.42 gm an d h as a measured volume of 4.7 cc. The possible error in the measurement of mass and volume are 0.01 gm and 0.1 cc. Then maximum error in the den sity will be [1991]a)22 %b)2 %c)0.2 %d)0.02 %Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A certain body weighs 22.42 gm an d h as a measured volume of 4.7 cc. The possible error in the measurement of mass and volume are 0.01 gm and 0.1 cc. Then maximum error in the den sity will be [1991]a)22 %b)2 %c)0.2 %d)0.02 %Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A certain body weighs 22.42 gm an d h as a measured volume of 4.7 cc. The possible error in the measurement of mass and volume are 0.01 gm and 0.1 cc. Then maximum error in the den sity will be [1991]a)22 %b)2 %c)0.2 %d)0.02 %Correct answer is option 'B'. Can you explain this answer?.
A certain body weighs 22.42 gm an d h as a measured volume of 4.7 cc. The possible error in the measurement of mass and volume are 0.01 gm and 0.1 cc. Then maximum error in the den sity will be [1991]a)22 %b)2 %c)0.2 %d)0.02 %Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A certain body weighs 22.42 gm an d h as a measured volume of 4.7 cc. The possible error in the measurement of mass and volume are 0.01 gm and 0.1 cc. Then maximum error in the den sity will be [1991]a)22 %b)2 %c)0.2 %d)0.02 %Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A certain body weighs 22.42 gm an d h as a measured volume of 4.7 cc. The possible error in the measurement of mass and volume are 0.01 gm and 0.1 cc. Then maximum error in the den sity will be [1991]a)22 %b)2 %c)0.2 %d)0.02 %Correct answer is option 'B'. Can you explain this answer?.
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A certain body weighs 22.42 gm an d h as a measured volume of 4.7 cc. The possible error in the measurement of mass and volume are 0.01 gm and 0.1 cc. Then maximum error in the den sity will be [1991]a)22 %b)2 %c)0.2 %d)0.02 %Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A certain body weighs 22.42 gm an d h as a measured volume of 4.7 cc. The possible error in the measurement of mass and volume are 0.01 gm and 0.1 cc. Then maximum error in the den sity will be [1991]a)22 %b)2 %c)0.2 %d)0.02 %Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A certain body weighs 22.42 gm an d h as a measured volume of 4.7 cc. The possible error in the measurement of mass and volume are 0.01 gm and 0.1 cc. Then maximum error in the den sity will be [1991]a)22 %b)2 %c)0.2 %d)0.02 %Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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