the resistivity of copper wire is of 1.7*10^-8 ohm metre .What lengt...
Resistivity, ρ=1.7 x 10^−8 ohm−mdiameter, d=0.1 mm=0.1 x 10−3 marea of cross section, A=πd^2/4resistance, R=34 ohmR=ρl/AR=ρl/(πd^2/4)34=1.7 x 10^−8 x l/3.14 x (0.1 x 10^−3)^2/4=> (34/(1.7 x 10^−8)) x 0.0314 x 10^−6/4=lSo, l = 15.7 m
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the resistivity of copper wire is of 1.7*10^-8 ohm metre .What lengt...
Calculation of Length of Copper Wire
To calculate the length of a copper wire with a given diameter that will have a resistance of 34 ohms, we can use the formula:
R = ρ * (L / A)
Where:
R is the resistance,
ρ (rho) is the resistivity of copper,
L is the length of the wire, and
A is the cross-sectional area of the wire.
Resistivity of Copper
The resistivity of copper is given as 1.7 * 10^-8 ohm metre.
Conversion of Diameter to Radius and Area
Given that the diameter of the wire is 0.1 mm, we can calculate the radius and the cross-sectional area of the wire.
The radius (r) is half of the diameter, so:
r = 0.1 mm / 2 = 0.05 mm = 0.05 * 10^-3 m
The cross-sectional area (A) of the wire is given by the formula:
A = π * r^2
Substituting the value of the radius, we get:
A = π * (0.05 * 10^-3)^2
Calculating the Length
Now, we can rearrange the resistance formula to solve for length:
L = (R * A) / ρ
Substituting the given values:
L = (34 * π * (0.05 * 10^-3)^2) / (1.7 * 10^-8)
Evaluating the expression and simplifying the units:
L = (34 * π * (0.05 * 10^-3)^2) / (1.7 * 10^-8)
L = (34 * 3.14 * (0.05 * 10^-3)^2) / (1.7 * 10^-8)
L = (34 * 3.14 * 0.0025 * 10^-6) / (1.7 * 10^-8)
L = (0.0269 * 10^-6) / (1.7 * 10^-8)
L = 1.58 m
Conclusion
Therefore, a copper wire with a diameter of 0.1 mm will have a length of approximately 1.58 meters to achieve a resistance of 34 ohms, assuming the resistivity of copper is 1.7 * 10^-8 ohm metre.
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