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If coordinates of two adjacent vertices of a Paralleogram are (3,2) (1,0) and diagonals bisect each other at (2,-5) find coordinates of the other two vertices?
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Here’s a detailed guide to finding the coordinates of the other two vertices of the parallelogram.
Given Information
- Two adjacent vertices: A(3, 2) and B(1, 0)
- Diagonal intersection point (midpoint): M(2, -5)
Understanding Parallelogram Properties
- In a parallelogram, the diagonals bisect each other.
- The midpoint M of the diagonals is also the midpoint of the segment connecting the two pairs of opposite vertices.
Finding Coordinates of the Other Vertices
1. Calculate the midpoint of AB:
- Midpoint formula: M = ((x1 + x2)/2, (y1 + y2)/2)
- For A(3, 2) and B(1, 0):
- M_AB = ((3 + 1)/2, (2 + 0)/2) = (2, 1)
2. Setting up the equation for diagonals:
- Since M is the midpoint of both diagonals, we have:
- M = (P + Q)/2, where P and Q are the other two vertices.
3. Using the midpoint of AB and M:
- Since M = (2, -5), we can set up the equations for P and Q:
- (P_x + Q_x)/2 = 2
- (P_y + Q_y)/2 = -5
4. Expressing P and Q coordinates:
- Let P = (x1, y1) and Q = (x2, y2).
- From the midpoint equations:
- x1 + x2 = 4
- y1 + y2 = -10
5. Finding P and Q:
- By substituting the values of the midpoint M_AB and setting up the system, we can derive:
- P = (3 + k, 2 - m)
- Q = (1 - k, 0 + m)
- Solve for k and m using the midpoint equations to find the exact coordinates of P and Q.
Final Coordinates
- The other two vertices of the parallelogram are:
- P(5, -8)
- Q(-1, -10)
This method effectively helps in determining the vertices by leveraging the properties of a parallelogram.
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If coordinates of two adjacent vertices of a Paralleogram are (3,2) (1,0) and diagonals bisect each other at (2,-5) find coordinates of the other two vertices?
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