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Draw a line segment of 8cm. & Find a point a on it which devides it in the ratio of 5:3?
Most Upvoted Answer
Draw a line segment of 8cm. & Find a point a on it which devides it in...
Steps of construction are :-
1.Draw line segment of length AB = 8 cm.

2. Draw any Ray  AX making acute ∠BAX with AB

3. Draw a parallel to BY parallel to AX by making∠ABY = ∠BAX.

4. Make 5 points A1, A2 ,A3, A4, A5 on AX & 3 points B1,B2,B3 ,on BY such that
AC1 = A1A2= A2A3 = A3A4= A4A5
= BB1 = B1B2 = B2B3

5.Join A5B4.Then it intersect AB at a point P.Thus P is the point of dividing AB internally in the ratio 5:3


That's all🙂
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Draw a line segment of 8cm. & Find a point a on it which devides it in...
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Draw a line segment of 8cm. & Find a point a on it which devides it in the ratio of 5:3?
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