Class 3 Maths - Multiplication - Question Answers

Question 1: Multiply 14 by 2.

Step 1: Arrange the numbers in columns.

Step 2: First multiply the ones digit by 2. 4 x 2 = 8. So, write 8 in the ones column.

Step 3: Next multiply the tens digits by 2. 1 x 2 = 2. So, we write 2 in the tens column.

Hence, 14 x 2 = 28

Question 2: Multiply 25 by 3.

Step 1: Write the numbers in columns.

Step 2: First multiply the ones digit by 3. 5 ones x 3 = 15 ones= 1 ten + 5 ones. So, we write 5 in the ones column and cany over 1 to the tens place.

Step 3: Next multiply the tens digit by 3. 2 tens x 3 = 6 tens. Add 1 ten (carried) to 6 tens. 6 tens + 1 ten = 7 tens. We write 7 in the tens column. So, 25 x 3 = 75

Hence, 25 x 3 = 75.

Question 3: Multiply 73 by 2.

Step 1: Write the numbers in columns.

Step 2: First multiply the ones digit by 2. 3 ones x 2 = 6 ones. So, we write 6 in the ones column.

Step 3: Next multiply the tens digit by 2. 7 tens x 2 = 14 tens = 1 hundred + 4 tens. So, we write 4 in the tens column and 1 below hundreds column.

So, 73 x 2 = 146.

Question 4: Multiply 78 by 4.

Step 1: Arrange the numbers in columns.

Step 2: First multiply the ones digit by 4. 8 ones x 4 = 32 ones = 3 tens + 2 ones. So, write 2 in the ones column and carry over 3 to tens column.

Step 3: Next multiply 7 tens by 4. 7 tens x 4 = 28 tens. Add 3 tens (carried) to 28 tens. 28 tens + 3 tens = 31 tens = 3 hundreds + 1 ten. So, write 1 below tens column and 3 below hundreds column.

So, 78 x 4 = 312.

Question 5: Estimate the sum 163 + 149 to the nearest hundred and verify its closeness to the actual sum.

Rounding off to nearest 100, we have
163 → 200 as 6 > 5 ⇒ 63 → 10 0 ⇒ 163 → 200
149 → 10 0 as 4 < 5 ⇒ 49 → 00 ⇒ 149 → 10 0
Thus, 163 + 149 → 200 + 100 = 300
Actual sum = 163 + 149 = 312.

Question 6: Estimate the difference 587 - 329 to the nearest 10 0, and also find the actual difference.

Rounding off to nearest 100, we have
587 → 600 as 8 > 5 ⇒ 87 → 10 0 or 587 → 600
and 329 → 300 as 2 < 5 ⇒ 29 → 00 or 329 → 300.
Thus, 587 - 329 → 600 - 300 = 300.
Actual difference = 587 - 329 = 258.

Question 7: Estimate the product of 33 and 18.

33 → 30 (rounding off to ten's place)
18 → 20 (rounding off to ten's place)
33 x 18 = 30 x 20 = 600.
Estimated product is 600.

Question 8: The cost of a chocolate is ₹ 12 Rohit bought 8 chocolates for his birthday party. How much did he spend on chocolates?

Cost of 1 chocolate = ₹ 12
Cost of 12 chocolates = ₹ 12  x 8 = ₹ 96
 
Hence, Rohit spent ₹ 96 on chocolates.

Question 9: A man sells 35 tickets every day. Find the number of tickets, he sells in 7 days.

In one day, the man sells 35 tickets.
In 7 days, he will sell 35 x 7 tickets.

Hence, the man sells 245 tickets in 7 days.