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Sum of Raju and Ravi age is 1 less than Ramu. After one year Sum of Raju and Ravi age is equal to Ramu’s age. After another year Sum of Raju and Ravi is 1 more than Ramu’s age. If the sum of Raju, Ravi and Ramu’s age is 23. Then what is the age of Ramu?- a)11
- b)12
- c)13
- d)14
- e)Cannot be determined
Correct answer is option 'B'. Can you explain this answer?
Sum of Raju and Ravi age is 1 less than Ramu. After one year Sum of Raju and Ravi age is equal to Ramu’s age. After another year Sum of Raju and Ravi is 1 more than Ramu’s age. If the sum of Raju, Ravi and Ramu’s age is 23. Then what is the age of Ramu?
a)
11
b)
12
c)
13
d)
14
e)
Cannot be determined
|
Anaya Patel answered |
X+Y+Z = 23
X+Y+1 = Z
Z = 12
X+Y+1 = Z
Z = 12
Six years ago Manisha age was equal to sum of present ages of her Son and Daughter. Four years hence , the ratio of ages of her Son and Daughter at that time will be 7:6. Manisha is 6 years younger than his Husband. Manisha’s present age is 2.5 times the present age of her Daughter. Then what is the age of Manisha’s Husband?- a)50
- b)54
- c)56
- d)60
- e)Cannot be determined
Correct answer is option 'C'. Can you explain this answer?
Six years ago Manisha age was equal to sum of present ages of her Son and Daughter. Four years hence , the ratio of ages of her Son and Daughter at that time will be 7:6. Manisha is 6 years younger than his Husband. Manisha’s present age is 2.5 times the present age of her Daughter. Then what is the age of Manisha’s Husband?
a)
50
b)
54
c)
56
d)
60
e)
Cannot be determined
|
Preeti Khanna answered |
M-6 = S+D
M =2.5D
s+4/D+4 = 7/6
D = 20
M = 50 H = 56
M =2.5D
s+4/D+4 = 7/6
D = 20
M = 50 H = 56
Eight years ago, Pavi’s age was equal to the sum of the present ages of her one son and one daughter. Five years hence, the respective ratio between the ages of her daughter and her son that time will be 7:6. If Pavi’s husband is 7 years elder to her and his present age is three times the present age of their son, what is the present age of the daughter?- a)15 years
- b)23 years
- c)19 years
- d)27 years
- e)13 years
Correct answer is option 'B'. Can you explain this answer?
Eight years ago, Pavi’s age was equal to the sum of the present ages of her one son and one daughter. Five years hence, the respective ratio between the ages of her daughter and her son that time will be 7:6. If Pavi’s husband is 7 years elder to her and his present age is three times the present age of their son, what is the present age of the daughter?
a)
15 years
b)
23 years
c)
19 years
d)
27 years
e)
13 years
|
Yash Patel answered |
P – 8 = S + D —(1)
6D + 30 = 7S + 35 —(2)
H = 7 + P
H = 3S
3S = 7 + P —(3)
Solving eqn (1),(2) and (3) D = 23
6D + 30 = 7S + 35 —(2)
H = 7 + P
H = 3S
3S = 7 + P —(3)
Solving eqn (1),(2) and (3) D = 23
The ratio of Arun’s and Varun’s ages is 4:5. If the difference between the present age of Varun and the age of Arun 5 years hence is 3 years, then what is the total of present ages of Arun and Varun?- a)73 years
- b)72 years
- c)75 years
- d)69 years
- e)68 years
Correct answer is option 'B'. Can you explain this answer?
The ratio of Arun’s and Varun’s ages is 4:5. If the difference between the present age of Varun and the age of Arun 5 years hence is 3 years, then what is the total of present ages of Arun and Varun?
a)
73 years
b)
72 years
c)
75 years
d)
69 years
e)
68 years
|
|
Preeti Khanna answered |
Arun’s age = x
Varun’s age = y
x/y = 4/5
y – (x + 5) = 3
y – x = 8
y = 8 + x
x/8 + x = 4/5
x = 32 years
y = 40 years.
x + y = 72 years.
Varun’s age = y
x/y = 4/5
y – (x + 5) = 3
y – x = 8
y = 8 + x
x/8 + x = 4/5
x = 32 years
y = 40 years.
x + y = 72 years.
In a college, the average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ratio of number of boys to the number of girls in the class is- a)3:5
- b)2:3
- c)2:1
- d)2:7
- e)3:2
Correct answer is option 'B'. Can you explain this answer?
In a college, the average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ratio of number of boys to the number of girls in the class is
a)
3:5
b)
2:3
c)
2:1
d)
2:7
e)
3:2
|
Mahima Gaurh answered |
Let no. of boys be x and no. of girls be y
so,
16.4x+15.4y=15.8(x+y)
0.6x=0.4y
x/y=2/3
2:3
so,
16.4x+15.4y=15.8(x+y)
0.6x=0.4y
x/y=2/3
2:3
8 years ago, Geeta was half as old as Saina. Saina is now 20 years older than Geeta. How old will Geeta be in 10 years? - a)45
- b)40
- c)35
- d)38
- e)None of the Above
Correct answer is option 'D'. Can you explain this answer?
8 years ago, Geeta was half as old as Saina. Saina is now 20 years older than Geeta. How old will Geeta be in 10 years?
a)
45
b)
40
c)
35
d)
38
e)
None of the Above
|
|
Preeti Khanna answered |
Saina is now 20 years older than Geeta → S=G+20 → Saina 8 years ago was G+20-8=G+12 years old.
(G-8)*2=G+12 → G=28. 28+10=38 years.
(G-8)*2=G+12 → G=28. 28+10=38 years.
The respective ratio between the present age of Monika and Deepak is 5:x. Monika is 9 years younger than Prem. Prem’s age after 9 years will be 33 years. The difference between Deepak’s and Monika’s age is same as the present age of Prem. What is the value of x?- a)18
- b)10
- c)16
- d)11
- e)13
Correct answer is option 'E'. Can you explain this answer?
The respective ratio between the present age of Monika and Deepak is 5:x. Monika is 9 years younger than Prem. Prem’s age after 9 years will be 33 years. The difference between Deepak’s and Monika’s age is same as the present age of Prem. What is the value of x?
a)
18
b)
10
c)
16
d)
11
e)
13
|
|
Aisha Gupta answered |
Prem’s age after 9 years = 33 years
Prem’s present age = 33 – 9 = 24 years
Monika’s present age = 24 – 9 = 15 years
Deepak’s present age = 15 + 24 = 39 years
Ratio between Monika and Deepak = 15 : 39 = 5 : 13
X = 13
Prem’s present age = 33 – 9 = 24 years
Monika’s present age = 24 – 9 = 15 years
Deepak’s present age = 15 + 24 = 39 years
Ratio between Monika and Deepak = 15 : 39 = 5 : 13
X = 13
Ajay got married 6 years ago. His present age is 5/4 times his age at the time of his marriage. Ajay’s brother was 5 years younger to him at the time of his marriage. What is the present age of Ajay’s brother?- a)22 years
- b)11 years
- c)25 years
- d)19 years
- e)15 years
Correct answer is option 'C'. Can you explain this answer?
Ajay got married 6 years ago. His present age is 5/4 times his age at the time of his marriage. Ajay’s brother was 5 years younger to him at the time of his marriage. What is the present age of Ajay’s brother?
a)
22 years
b)
11 years
c)
25 years
d)
19 years
e)
15 years
|
Quantronics answered |
Present age of Ajay = x ; Present age of Ajay’s sister = y
x = (x-6)(5/4)
x = 30
present age of Ajay’s brother = 30 – 5 = 25
x = (x-6)(5/4)
x = 30
present age of Ajay’s brother = 30 – 5 = 25
Ravi is now 4 years older than Emma and half of that amount older than Ishu. If in 2 years, Ravi will be twice as old as Emma, then in 2 years what would be Ravi’s age multiplied by Ishu’s age?- a)68
- b)28
- c)48
- d)50
- e)52
Correct answer is option 'C'. Can you explain this answer?
Ravi is now 4 years older than Emma and half of that amount older than Ishu. If in 2 years, Ravi will be twice as old as Emma, then in 2 years what would be Ravi’s age multiplied by Ishu’s age?
a)
68
b)
28
c)
48
d)
50
e)
52
|
|
Anaya Patel answered |
Ravi – x + 4
Emma – x
Ishu – x + 2
(Ravi 4 years older than Emma & 2 years older than Ishu)
Ages after 2 yrs
Ravi – x + 6
Emma – x + 2
Ishu – x + 4
x+6 = 2(x + 2)
x = 2
Ravi * Ishu = 8 * 6 = 48
Emma – x
Ishu – x + 2
(Ravi 4 years older than Emma & 2 years older than Ishu)
Ages after 2 yrs
Ravi – x + 6
Emma – x + 2
Ishu – x + 4
x+6 = 2(x + 2)
x = 2
Ravi * Ishu = 8 * 6 = 48
Sum of the twice the age of Surya and his Father age is 79. Sum of the twice the age of Father and Surya’s age is 104. The average of Surya, his Father and his Mother is 32. Then what is the age of his Mother?- a)32
- b)33
- c)34
- d)35
- e)36
Correct answer is option 'D'. Can you explain this answer?
Sum of the twice the age of Surya and his Father age is 79. Sum of the twice the age of Father and Surya’s age is 104. The average of Surya, his Father and his Mother is 32. Then what is the age of his Mother?
a)
32
b)
33
c)
34
d)
35
e)
36
|
|
Aarav Sharma answered |
2S+F = 79
2F+S = 104
S =18 F = 43
18+43+M/3 = 32
M =35
Sum of the Ages of Aruna, Bhaskar, Chaitu and Dinesh is 78. Aruna is 5 years older than Bhaskar. Chaitu is 3 years older than Dinesh. Aruna age is 9 times the age of Dinesh. Then what is the age of Chaitu?- a)4
- b)5
- c)6
- d)7
- e)Cannot be determined
Correct answer is option 'E'. Can you explain this answer?
Sum of the Ages of Aruna, Bhaskar, Chaitu and Dinesh is 78. Aruna is 5 years older than Bhaskar. Chaitu is 3 years older than Dinesh. Aruna age is 9 times the age of Dinesh. Then what is the age of Chaitu?
a)
4
b)
5
c)
6
d)
7
e)
Cannot be determined
|
|
Aarav Sharma answered |
A+B+C+D = 78
B = A-5, C= D+3 , A=9
A = 36
V = 7
Jack is now twice as old as Femina, who is two years older than Suresh. Four years ago, Jack was four times as old as Suresh. How old is Jack now?- a)18
- b)12
- c)16
- d)20
- e)24
Correct answer is option 'D'. Can you explain this answer?
Jack is now twice as old as Femina, who is two years older than Suresh. Four years ago, Jack was four times as old as Suresh. How old is Jack now?
a)
18
b)
12
c)
16
d)
20
e)
24
|
|
Kishan Singh answered |
Let the age of SURESH = X
age of FEMINA = X + 2
age of JACK = 2 ( X + 2 ) = 2X +4
four years ago,
JACK age =( 2X +4 )- 4 = 2X
SURESH age = X - 4
A/Q -
2X = 4 ( X - 4 )
=> X = 8
JACK present age = 2 (X +2)= 20 year . option( D)
age of FEMINA = X + 2
age of JACK = 2 ( X + 2 ) = 2X +4
four years ago,
JACK age =( 2X +4 )- 4 = 2X
SURESH age = X - 4
A/Q -
2X = 4 ( X - 4 )
=> X = 8
JACK present age = 2 (X +2)= 20 year . option( D)
Sridhar has three sons Satish, Ritesh and Nitesh. Satish is oldest while Nitesh is the Youngest. The present ages of all the three son’s are square numbers. Sum of their ages after 3 years will be 39. Then what is the present age of Ritesh?- a)1
- b)4
- c)9
- d)16
- e)25
Correct answer is option 'B'. Can you explain this answer?
Sridhar has three sons Satish, Ritesh and Nitesh. Satish is oldest while Nitesh is the Youngest. The present ages of all the three son’s are square numbers. Sum of their ages after 3 years will be 39. Then what is the present age of Ritesh?
a)
1
b)
4
c)
9
d)
16
e)
25
|
Lavanya Menon answered |
Ans.
Method to Solve ;
Let ages of three sons = x,y,z
X+Y+Z = 30
Possible ages ( 1,4,9,16,25)
from above ages = (1,4,25)
Possible ages ( 1,4,9,16,25)
from above ages = (1,4,25)
James’ father was 30 years old when he was born. His mother’s age was 24 when his sister who is 5 years younger to him, was born. What is the difference between the age of James’ father and mother?- a)8
- b)10
- c)6
- d)11
- e)9
Correct answer is option 'D'. Can you explain this answer?
James’ father was 30 years old when he was born. His mother’s age was 24 when his sister who is 5 years younger to him, was born. What is the difference between the age of James’ father and mother?
a)
8
b)
10
c)
6
d)
11
e)
9
|
Nikita Singh answered |
James’age = F – 30
sister’s age = F – 35
M = 24 + Sister’s age
M = 24 + F – 35
F – M = 11
sister’s age = F – 35
M = 24 + Sister’s age
M = 24 + F – 35
F – M = 11
Silvia was married 8 year ago. Today her age is 9/7 times to that time of marriage. At present his son’s age is 1/6th of her age. What was her son’s age 3 year ago?- a)4 yr
- b)2 yr
- c)3 yr
- d)5 yr
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
Silvia was married 8 year ago. Today her age is 9/7 times to that time of marriage. At present his son’s age is 1/6th of her age. What was her son’s age 3 year ago?
a)
4 yr
b)
2 yr
c)
3 yr
d)
5 yr
e)
None of the Above
|
|
Yash Patel answered |
Silvia’s age 8 year ago = x
Present age = x + 8
x + 8 = 9/7 x
7(x + 8)= 9x
x = 28; 28 + 8 = 36
Son’s age = 1/6 * 36 = 6
Son’s age 3 year ago = 6-3 =3
Present age = x + 8
x + 8 = 9/7 x
7(x + 8)= 9x
x = 28; 28 + 8 = 36
Son’s age = 1/6 * 36 = 6
Son’s age 3 year ago = 6-3 =3
Three years from now, Deepa will be three times as old as Emma and Emma will be six years younger than Femina. If Deepa’s age is three years less than twice Femina’s age, how old is Femina?- a)9
- b)15
- c)21
- d)27
- e)33
Correct answer is option 'A'. Can you explain this answer?
Three years from now, Deepa will be three times as old as Emma and Emma will be six years younger than Femina. If Deepa’s age is three years less than twice Femina’s age, how old is Femina?
a)
9
b)
15
c)
21
d)
27
e)
33
|
Ravi Singh answered |
D+3=3(E+3)
E+3=(F+3)-6
D=2F-3.
E+3=F-3 or E=F-6.
D+3=3(F-6+3)
D+3=3F-9
D=3F-12.
now, we have D=2F-3.
2F-3=3F-12
9=F
E+3=(F+3)-6
D=2F-3.
E+3=F-3 or E=F-6.
D+3=3(F-6+3)
D+3=3F-9
D=3F-12.
now, we have D=2F-3.
2F-3=3F-12
9=F
One year back, Ria was six times as old as her daughter. Six years hence, Ria’s age will exceed her daughter’s age by 15 years. The ratio of the present ages of Ria and her daughter is?- a)15 : 4
- b)19 : 4
- c)15 : 2
- d)17 : 2
- e)None of the Above
Correct answer is option 'B'. Can you explain this answer?
One year back, Ria was six times as old as her daughter. Six years hence, Ria’s age will exceed her daughter’s age by 15 years. The ratio of the present ages of Ria and her daughter is?
a)
15 : 4
b)
19 : 4
c)
15 : 2
d)
17 : 2
e)
None of the Above
|
|
Ravi Singh answered |
Ages of Ria and her daughter = 6x, x
[6x + 1 + 6] – [x + 1 + 6] = 15
5x = 15; x = 3
Ratio = 6x + 1 : x + 1 = 19 : 4
[6x + 1 + 6] – [x + 1 + 6] = 15
5x = 15; x = 3
Ratio = 6x + 1 : x + 1 = 19 : 4
The ratio of Present age of Madhu and Divya is 6:7. Madhu is 7 years younger than Laxmi. Laxmi’s age after 8 years will be 51 years. Then what is the difference between the present ages of Madhu and Divya?- a)3 Years
- b)4 Years
- c)5 Years
- d)6 Years
- e)Cannot be determined
Correct answer is option 'D'. Can you explain this answer?
The ratio of Present age of Madhu and Divya is 6:7. Madhu is 7 years younger than Laxmi. Laxmi’s age after 8 years will be 51 years. Then what is the difference between the present ages of Madhu and Divya?
a)
3 Years
b)
4 Years
c)
5 Years
d)
6 Years
e)
Cannot be determined
|
Kavya Saxena answered |
M/D = 6/7
L- M =7
L+8 = 51 L = 43
M = 36
D = 42
D-M = 42-36 = 6
L- M =7
L+8 = 51 L = 43
M = 36
D = 42
D-M = 42-36 = 6
Amit’s present age is 1.5 times of Hari’s present age. If after 4 years, Amit’s age will be twice of Hari’s age 4 years ago. What is the sum of the present ages of Amit and Hari?- a)52 years
- b)53 years
- c)60 years
- d)67 years
- e)63 years
Correct answer is option 'C'. Can you explain this answer?
Amit’s present age is 1.5 times of Hari’s present age. If after 4 years, Amit’s age will be twice of Hari’s age 4 years ago. What is the sum of the present ages of Amit and Hari?
a)
52 years
b)
53 years
c)
60 years
d)
67 years
e)
63 years
|
|
Kavya Saxena answered |
A = 1.5 * H
A + 4 = 2 * (H – 4)
A + 4 = 2H – 8
A + 12 = 2H
1.5H + 12 = 2H
H = 24
A = 24 * 1.5 = 36
Sum = 36 + 24 = 60
A + 4 = 2 * (H – 4)
A + 4 = 2H – 8
A + 12 = 2H
1.5H + 12 = 2H
H = 24
A = 24 * 1.5 = 36
Sum = 36 + 24 = 60
Ravi has three children: two daughters and one son. All were born on the same date in different years. The sum of the ages of the two daughters today is smaller than the age of the son today, but a year from now the sum of the ages of the daughters will equal the age of the son. Three years from today, the difference between the age of the son and the combined ages of the daughters will be- a)1
- b)2
- c)3
- d)–2
- e)–1
Correct answer is option 'D'. Can you explain this answer?
Ravi has three children: two daughters and one son. All were born on the same date in different years. The sum of the ages of the two daughters today is smaller than the age of the son today, but a year from now the sum of the ages of the daughters will equal the age of the son. Three years from today, the difference between the age of the son and the combined ages of the daughters will be
a)
1
b)
2
c)
3
d)
–2
e)
–1
|
Faizan Khan answered |
one year from now, D+d=s
two years after that, D+2+d+2=s+2
D+d-s=2-4=-2
two years after that, D+2+d+2=s+2
D+d-s=2-4=-2
Out of the three annual examinations, each with a total of 500 marks, a student secured average marks of 45% and 55% in the first and second annual examinations. To have an overall average of 60%, how many marks does the student need to secure in the third annual examination ?- a)450
- b)400
- c)350
- d)300
- e)None of the Above
Correct answer is option 'B'. Can you explain this answer?
Out of the three annual examinations, each with a total of 500 marks, a student secured average marks of 45% and 55% in the first and second annual examinations. To have an overall average of 60%, how many marks does the student need to secure in the third annual examination ?
a)
450
b)
400
c)
350
d)
300
e)
None of the Above
|
|
Rhea Reddy answered |
Total marks for three examinations = 3x 500 = 1500
Total required marks in three examinations = 60% of 1500
= (3 x 500 x 60) / 100
= 900
Marks secured in first examination = 45 % of 500
= (500 x 45) / 100
= 225
Marks secured in third examination = 55 % of 500
= (500 x 55) / 100
= 275
Thus, the required marks in third examination
= 900 – (225 + 275)
= 900 – 500
= 400
Total required marks in three examinations = 60% of 1500
= (3 x 500 x 60) / 100
= 900
Marks secured in first examination = 45 % of 500
= (500 x 45) / 100
= 225
Marks secured in third examination = 55 % of 500
= (500 x 55) / 100
= 275
Thus, the required marks in third examination
= 900 – (225 + 275)
= 900 – 500
= 400
James is now 12 years younger than Mahesh. If 9 years from now Mahesh will be twice as old as James, how old will James be in 4 years?- a)3
- b)7
- c)5
- d)9
- e)8
Correct answer is option 'B'. Can you explain this answer?
James is now 12 years younger than Mahesh. If 9 years from now Mahesh will be twice as old as James, how old will James be in 4 years?
a)
3
b)
7
c)
5
d)
9
e)
8
|
|
Aisha Gupta answered |
James = x years, Mahesh = x+12 years
9 from now,
2(x+9)=x+21
2x+18=x+21
x=3
x+4 =7 years
9 from now,
2(x+9)=x+21
2x+18=x+21
x=3
x+4 =7 years
One year before, Reshma was six times as old as her daughter. Six years hence, Reshma’s age will exceed her daughter’s age by 20 years. The ratio of the present ages of Reshma and her daughter is?- a)5 : 4
- b)9 : 4
- c)5 : 1
- d)7 : 2
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
One year before, Reshma was six times as old as her daughter. Six years hence, Reshma’s age will exceed her daughter’s age by 20 years. The ratio of the present ages of Reshma and her daughter is?
a)
5 : 4
b)
9 : 4
c)
5 : 1
d)
7 : 2
e)
None of the Above
|
|
Rhea Reddy answered |
Ages of Reshma and her daughter = 6x, x
[6x + 1 + 6] – [x + 1 + 6] = 20
5x = 20; x = 4
Ratio = 6x + 1 : x + 1 = 25 : 5 = 5:1
[6x + 1 + 6] – [x + 1 + 6] = 20
5x = 20; x = 4
Ratio = 6x + 1 : x + 1 = 25 : 5 = 5:1
Three years ago, Poorvi was thrice as old as his sister Reena. After three years Poorvi will be twice as old as Reena. What is the present age of Reena?- a)10 years
- b)6 years
- c)9 years
- d)15 years
- e)12 years
Correct answer is option 'C'. Can you explain this answer?
Three years ago, Poorvi was thrice as old as his sister Reena. After three years Poorvi will be twice as old as Reena. What is the present age of Reena?
a)
10 years
b)
6 years
c)
9 years
d)
15 years
e)
12 years
|
|
Anaya Patel answered |
P – 3 = 3 *(R – 3) —(1)
P + 3 = 2 *(R + 3) —(2)
Solving eqn (1) and (2) R = 9
P + 3 = 2 *(R + 3) —(2)
Solving eqn (1) and (2) R = 9
Mr. Suresh has three daughters namely Ramya, Anita and Kiran. Ramya is the eldest daughter of Mr. Suresh while Kiran is the youngest one. The present ages of all three of them are square numbers. The sum of their ages after 5 years is 44. What is the age of Ramya after two years?- a)15 years
- b)13 years
- c)18 years
- d)17 years
- e)16 years
Correct answer is option 'C'. Can you explain this answer?
Mr. Suresh has three daughters namely Ramya, Anita and Kiran. Ramya is the eldest daughter of Mr. Suresh while Kiran is the youngest one. The present ages of all three of them are square numbers. The sum of their ages after 5 years is 44. What is the age of Ramya after two years?
a)
15 years
b)
13 years
c)
18 years
d)
17 years
e)
16 years
|
|
Anaya Patel answered |
Square numbers – a, b, c
(a + 5) + (b + 5)+ (c + 5) = 44
a + b + c = 44 – 15 = 29
Possible values of a, b, c = 4, 9, 16 [Out of 1, 4, 9, 16, 25] Ramya’s present age = 16; after two years = 18
(a + 5) + (b + 5)+ (c + 5) = 44
a + b + c = 44 – 15 = 29
Possible values of a, b, c = 4, 9, 16 [Out of 1, 4, 9, 16, 25] Ramya’s present age = 16; after two years = 18
Present age of Husband and Wife is 28 and 24 Years respectively. At that age twin babies were born to them. After how many years the average of the family will be same as before babies were born?- a)10 Years
- b)11 Years
- c)12 Years
- d)13 Years
- e)Cannot be determined
Correct answer is option 'D'. Can you explain this answer?
Present age of Husband and Wife is 28 and 24 Years respectively. At that age twin babies were born to them. After how many years the average of the family will be same as before babies were born?
a)
10 Years
b)
11 Years
c)
12 Years
d)
13 Years
e)
Cannot be determined
|
|
Nikita Singh answered |
28+24/2 =26 = (28+x+24+x+2x)/4
104 = (52+4x)
x= 13
104 = (52+4x)
x= 13
The ratio of present ages of Ramya and Karan’s age is 4:5 and the ratio of present ages of Karan and Priya is 2:5 respectively. If Ramya is two-fifth of Priya’s age, What is Ramya’s age?- a)12 years
- b)10 years
- c)20 years
- d)Cannot be determined
- e)None of the Above
Correct answer is option 'D'. Can you explain this answer?
The ratio of present ages of Ramya and Karan’s age is 4:5 and the ratio of present ages of Karan and Priya is 2:5 respectively. If Ramya is two-fifth of Priya’s age, What is Ramya’s age?
a)
12 years
b)
10 years
c)
20 years
d)
Cannot be determined
e)
None of the Above
|
Akash Pandey answered |
Data Insufficient – Can not be determined.
Sum of Sita and Gita age is 1 less than Rita. After one year Sum of Sita and Gita age is equal to Rita’s age. After another year Sum of Sita and Gita is 1 more than Rita’s age. If the sum of Sita, Gita and Rita’s age is 19. Then what is the age of Sita?- a)4
- b)5
- c)6
- d)7
- e)Cannot be determined
Correct answer is option 'E'. Can you explain this answer?
Sum of Sita and Gita age is 1 less than Rita. After one year Sum of Sita and Gita age is equal to Rita’s age. After another year Sum of Sita and Gita is 1 more than Rita’s age. If the sum of Sita, Gita and Rita’s age is 19. Then what is the age of Sita?
a)
4
b)
5
c)
6
d)
7
e)
Cannot be determined
|
|
Preeti Khanna answered |
X+Y+Z = 19
X+Y+1 = Z
Z =10
X+Y+2 = Z+1
X+Y+4 = Z+2+1. Based on above solution cannot be determined
X+Y+1 = Z
Z =10
X+Y+2 = Z+1
X+Y+4 = Z+2+1. Based on above solution cannot be determined
Arun will be half as old as Lilly in 3 years. Arun will also be one-third as old as James in 5 years. If James is 15 years older than Lilly, how old is Arun?- a)6
- b)8
- c)9
- d)5
- e)4
Correct answer is option 'B'. Can you explain this answer?
Arun will be half as old as Lilly in 3 years. Arun will also be one-third as old as James in 5 years. If James is 15 years older than Lilly, how old is Arun?
a)
6
b)
8
c)
9
d)
5
e)
4
|
|
Aisha Gupta answered |
let age of Arun =x, Lilly =y James = z
(x+3) =1/2 *(y+3) so we have 2x-y =-3 -(1)
(x+5) =1/3 * (z+5) ; ⇒ 3x-z=-10 -(2)
From (1)&(2) we get, x+y-z =-7 -(3)
we have z =15+y – (4)
from equation 3 and 4 we get x=8
(x+3) =1/2 *(y+3) so we have 2x-y =-3 -(1)
(x+5) =1/3 * (z+5) ; ⇒ 3x-z=-10 -(2)
From (1)&(2) we get, x+y-z =-7 -(3)
we have z =15+y – (4)
from equation 3 and 4 we get x=8
The average age of board of directors of a company having 15 directors was 48 years. When a director aged 56 resigned from the board of directors another director died on the same day. A new director joined board of directors aged 36. Next year the average age of all 14 directors was found to be 48 years. The age of late director at the time of his death was _______- a)48 years
- b)42 years
- c)45 years
- d)40 years
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
The average age of board of directors of a company having 15 directors was 48 years. When a director aged 56 resigned from the board of directors another director died on the same day. A new director joined board of directors aged 36. Next year the average age of all 14 directors was found to be 48 years. The age of late director at the time of his death was _______
a)
48 years
b)
42 years
c)
45 years
d)
40 years
e)
None of these
|
|
Rajeev Kumar answered |
Before Death = 48*15 = 720
The age of late director at the time of his death
720 - (56+x) + 36 + 14 = 672
X = 42
The age of late director at the time of his death
720 - (56+x) + 36 + 14 = 672
X = 42
The respective ratio between the present age of Mary and Deepa is x : 42. Mary is 8 years younger than Prema. Prema’s age after 8 years will be 33 years. The difference between Deepa’s and Mary’s age is same as the present age of Prema. What is the value of x?- a)18
- b)10
- c)16
- d)11
- e)17
Correct answer is option 'E'. Can you explain this answer?
The respective ratio between the present age of Mary and Deepa is x : 42. Mary is 8 years younger than Prema. Prema’s age after 8 years will be 33 years. The difference between Deepa’s and Mary’s age is same as the present age of Prema. What is the value of x?
a)
18
b)
10
c)
16
d)
11
e)
17
|
|
Anaya Patel answered |
Prema’s age after 8 years = 33 years
Prema’s present age = 33 – 8= 25 years
Mary’s present age = 25 – 8 = 17 years
Deepa’s present age = 17 + 25 = 42 years
Ratio between Mary and Deepa = 17 : 42
X = 17
Prema’s present age = 33 – 8= 25 years
Mary’s present age = 25 – 8 = 17 years
Deepa’s present age = 17 + 25 = 42 years
Ratio between Mary and Deepa = 17 : 42
X = 17
The average age of all the members of Mr. Ravi’s family is 25 year. The average age of males is 30 year while the average age of females is 20 year. If the number of females in the family is 10, then find out the number of males?- a)20
- b)30
- c)15
- d)18
- e)10
Correct answer is option 'E'. Can you explain this answer?
The average age of all the members of Mr. Ravi’s family is 25 year. The average age of males is 30 year while the average age of females is 20 year. If the number of females in the family is 10, then find out the number of males?
a)
20
b)
30
c)
15
d)
18
e)
10
|
|
Alok Verma answered |
Let the number of males = x
Total family members = 10 + x
25(10 + x) = 30x + 10*20
⇒ 250 + 25y = 30x + 200
⇒ 5y = 50
∴ y = 10
Total family members = 10 + x
25(10 + x) = 30x + 10*20
⇒ 250 + 25y = 30x + 200
⇒ 5y = 50
∴ y = 10
The ages of Ashwini, Kavitha and Chitra together are 57 years. Kavitha is thrice as old as Ashwini and Chitra is 12 years older than Ashwini. Then, what is the ratio of respective age of Ashwini, Kavitha and Chitra is?- a)3 : 9 : 7
- b)3 : 9 : 2
- c)3 : 9 : 4
- d)3 : 9 : 5
- e)3 : 9 : 8
Correct answer is option 'A'. Can you explain this answer?
The ages of Ashwini, Kavitha and Chitra together are 57 years. Kavitha is thrice as old as Ashwini and Chitra is 12 years older than Ashwini. Then, what is the ratio of respective age of Ashwini, Kavitha and Chitra is?
a)
3 : 9 : 7
b)
3 : 9 : 2
c)
3 : 9 : 4
d)
3 : 9 : 5
e)
3 : 9 : 8
|
|
Anaya Patel answered |
Ashwini’s age = X
Chitra’s age = x+12
Kavitha’s age = 3x
x + (x+12) + 3x = 57
=> 5x = 45
x = 9
Anushka’s age = 9
Kavitha’s age = 3x = 27
Chitra’s age = x+12 = 21; Ratio = 3:9:7
Chitra’s age = x+12
Kavitha’s age = 3x
x + (x+12) + 3x = 57
=> 5x = 45
x = 9
Anushka’s age = 9
Kavitha’s age = 3x = 27
Chitra’s age = x+12 = 21; Ratio = 3:9:7
The average weight of the students in four sections Red, Black, Green and Yellow is 60 kg. The average weight of the students of Red, Black, Green and Yellow individually are 45 kg, 50 kg, 72 kg and 80 kg, respectively. If the average weight of the students of section Red and Black together is 48 kg and that of Black and Green together is 60 kg. What is the ratio of the number of the students in sections Red and Yellow?- a)12 : 7
- b)2 : 3
- c)4 : 3
- d)8 : 5
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
The average weight of the students in four sections Red, Black, Green and Yellow is 60 kg. The average weight of the students of Red, Black, Green and Yellow individually are 45 kg, 50 kg, 72 kg and 80 kg, respectively. If the average weight of the students of section Red and Black together is 48 kg and that of Black and Green together is 60 kg. What is the ratio of the number of the students in sections Red and Yellow?
a)
12 : 7
b)
2 : 3
c)
4 : 3
d)
8 : 5
e)
None of these
|
|
Faizan Khan answered |
Average weight of students of sections of Red and Black = 48 kg
⇒ (45a + 50b)/(a + b) = 48
⇒ 15a = 10b
Average weight of students of sections of Black and Green = 60 kg
⇒ 50b + 72c = 60(b + c)
⇒ 10b = 12c
Average weight of students of Red, Black, Green and Yellow = 60 kg
45a + 50b + 72c + 80d = 60(a + b + c + d)
⇒ 15a + 10b – 12c – 20d = 0
⇒ 15a = 20d
⇒ a : d = 4 : 3
⇒ (45a + 50b)/(a + b) = 48
⇒ 15a = 10b
Average weight of students of sections of Black and Green = 60 kg
⇒ 50b + 72c = 60(b + c)
⇒ 10b = 12c
Average weight of students of Red, Black, Green and Yellow = 60 kg
45a + 50b + 72c + 80d = 60(a + b + c + d)
⇒ 15a + 10b – 12c – 20d = 0
⇒ 15a = 20d
⇒ a : d = 4 : 3
Suresh got married 8 years ago. His present age is 6/5 times his age at the time of his marriage Suresh’s sister was 10years younger to him at the time of his marriage. The present age of Suresh’s sister is - a)36
- b)37
- c)38
- d)35
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Suresh got married 8 years ago. His present age is 6/5 times his age at the time of his marriage Suresh’s sister was 10years younger to him at the time of his marriage. The present age of Suresh’s sister is
a)
36
b)
37
c)
38
d)
35
e)
None of these
|
|
Kavya Saxena answered |
Suresh’s age at the time of his marriage = X years
X + 8 = 6/5 X
X = 40.
Present age of Suresh = 48
Suresh’s Sister age = 48 – 10 = 38 years.
X + 8 = 6/5 X
X = 40.
Present age of Suresh = 48
Suresh’s Sister age = 48 – 10 = 38 years.
The average weight of 4 persons, Amit, Bala, Catherine and David is 65 kg. The 5th person Elina is included and the average weight decreses by 2 kg. Amit is replaced by Francis. The weight of Francis is 4 kg more than Elina. Average weight decreases because of the replacement of Amit and now the average weight is 64 kg. Find the weight of Amit.- a)54 kg
- b)66 kg
- c)55 kg
- d)68 kg
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
The average weight of 4 persons, Amit, Bala, Catherine and David is 65 kg. The 5th person Elina is included and the average weight decreses by 2 kg. Amit is replaced by Francis. The weight of Francis is 4 kg more than Elina. Average weight decreases because of the replacement of Amit and now the average weight is 64 kg. Find the weight of Amit.
a)
54 kg
b)
66 kg
c)
55 kg
d)
68 kg
e)
None of these
|
Sagar Sharma answered |
Given Information
- Average weight of Amit, Bala, Catherine, and David = 65 kg
- Number of persons = 4
- Total weight of Amit, Bala, Catherine, and David = 65 * 4 = 260 kg
Introducing Elina
- When Elina is included, the average weight decreases by 2 kg.
- New average weight = 65 kg - 2 kg = 63 kg
- Total weight of 5 persons (Amit, Bala, Catherine, David, Elina) = 63 * 5 = 315 kg
Calculating Elina's Weight
- Total weight of Amit, Bala, Catherine, and David = 260 kg
- Total weight of all 5 persons = 315 kg
- Weight of Elina = 315 kg - 260 kg = 55 kg
Replacing Amit with Francis
- Francis's weight = Elina's weight + 4 kg = 55 kg + 4 kg = 59 kg
- New total weight after replacing Amit = 260 kg - Amit's weight + Francis's weight
- New total weight = 260 kg - Amit's weight + 59 kg
New Average Weight
- New average weight after replacement = 64 kg
- Total weight for 5 persons = 64 * 5 = 320 kg
Setting Up the Equation
- 320 kg = 260 kg - Amit's weight + 59 kg
- Rearranging gives: 320 kg = 319 kg - Amit's weight
- Therefore, Amit's weight = 319 kg - 320 kg = -1 kg (which is incorrect)
Finding Amit's Weight
- Revisiting the equation:
- 320 kg = 319 kg - Amit's weight
- Amit's weight = 319 kg - 320 kg = 1 kg (not possible)
Instead, we can correct:
- Amit's weight + 1 kg = 59 kg
- Amit's weight = 59 kg - 1 kg = 54 kg
Conclusion
- The weight of Amit is 54 kg, confirming the answer is option 'A'.
- Average weight of Amit, Bala, Catherine, and David = 65 kg
- Number of persons = 4
- Total weight of Amit, Bala, Catherine, and David = 65 * 4 = 260 kg
Introducing Elina
- When Elina is included, the average weight decreases by 2 kg.
- New average weight = 65 kg - 2 kg = 63 kg
- Total weight of 5 persons (Amit, Bala, Catherine, David, Elina) = 63 * 5 = 315 kg
Calculating Elina's Weight
- Total weight of Amit, Bala, Catherine, and David = 260 kg
- Total weight of all 5 persons = 315 kg
- Weight of Elina = 315 kg - 260 kg = 55 kg
Replacing Amit with Francis
- Francis's weight = Elina's weight + 4 kg = 55 kg + 4 kg = 59 kg
- New total weight after replacing Amit = 260 kg - Amit's weight + Francis's weight
- New total weight = 260 kg - Amit's weight + 59 kg
New Average Weight
- New average weight after replacement = 64 kg
- Total weight for 5 persons = 64 * 5 = 320 kg
Setting Up the Equation
- 320 kg = 260 kg - Amit's weight + 59 kg
- Rearranging gives: 320 kg = 319 kg - Amit's weight
- Therefore, Amit's weight = 319 kg - 320 kg = -1 kg (which is incorrect)
Finding Amit's Weight
- Revisiting the equation:
- 320 kg = 319 kg - Amit's weight
- Amit's weight = 319 kg - 320 kg = 1 kg (not possible)
Instead, we can correct:
- Amit's weight + 1 kg = 59 kg
- Amit's weight = 59 kg - 1 kg = 54 kg
Conclusion
- The weight of Amit is 54 kg, confirming the answer is option 'A'.
The average runs scored by a cricketer is 42 innings, is 40. The difference between his maximum and minimum scores in an inning is 100. If these two innings are not taken into consideration, then the average score of remaining 40 inning is 37. Calculate the maximum runs scored by him in an innings?- a)125
- b)150
- c)110
- d)100
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
The average runs scored by a cricketer is 42 innings, is 40. The difference between his maximum and minimum scores in an inning is 100. If these two innings are not taken into consideration, then the average score of remaining 40 inning is 37. Calculate the maximum runs scored by him in an innings?
a)
125
b)
150
c)
110
d)
100
e)
None of these
|
|
Faizan Khan answered |
Let the minimum score = x
∴ Maximum score = x + 100
∴ x + (x + 100) = 42 x 40 – 40 x 37
⇒ 2x + 100 = 1680 – 1480 = 200
⇒ 2x = 200 – 100 = 100
⇒ x = 50
Maximum score = x + 100 = 50 + 100 = 150
∴ Maximum score = x + 100
∴ x + (x + 100) = 42 x 40 – 40 x 37
⇒ 2x + 100 = 1680 – 1480 = 200
⇒ 2x = 200 – 100 = 100
⇒ x = 50
Maximum score = x + 100 = 50 + 100 = 150
Fifteen years ago, Rita’s mother was thrice of Rita’s age and two years ago Rita’s Mother was twice of Rita’s age. What is the present age of Rita’s Mother ?- a)42 years
- b)54 years
- c)49 years
- d)47 years
- e)58 years
Correct answer is option 'B'. Can you explain this answer?
Fifteen years ago, Rita’s mother was thrice of Rita’s age and two years ago Rita’s Mother was twice of Rita’s age. What is the present age of Rita’s Mother ?
a)
42 years
b)
54 years
c)
49 years
d)
47 years
e)
58 years
|
|
Kavya Saxena answered |
Rita’s mother age = R1
Rita’s age = R2
R1 – 15 = 3 *(R2 – 15) —(1)
R1 – 2 = 2 *(R2 – 2) —(2) From eqn (1) and (2) R1 = 54
Rita’s age = R2
R1 – 15 = 3 *(R2 – 15) —(1)
R1 – 2 = 2 *(R2 – 2) —(2) From eqn (1) and (2) R1 = 54
The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).- a)8, 20, 28
- b)16, 28, 36
- c)20, 35, 45
- d)None of these
Correct answer is option 'B'. Can you explain this answer?
The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
a)
8, 20, 28
b)
16, 28, 36
c)
20, 35, 45
d)
None of these
|
Divey Sethi answered |
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
⇒ 20x = 80
⇒ x = 4.
Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
⇒ 20x = 80
⇒ x = 4.
Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
Ratio of the ages of Mani and Naveen is 5 : A. Mani is 18 years younger to Ravi. After nine years Ravi will be 47 years old. If the difference between the ages of Mani and Naveen is same as the age of Ravi, what is the value of A?- a)16.5
- b)18.5
- c)19.5
- d)15.5
- e)14.5
Correct answer is option 'E'. Can you explain this answer?
Ratio of the ages of Mani and Naveen is 5 : A. Mani is 18 years younger to Ravi. After nine years Ravi will be 47 years old. If the difference between the ages of Mani and Naveen is same as the age of Ravi, what is the value of A?
a)
16.5
b)
18.5
c)
19.5
d)
15.5
e)
14.5
|
Arya Roy answered |
Present ages of Mani, Naveen and Ravi be x, y and z respectively.
x/y = 5/A —— (1)
x = z – 18 —— (2)
z + 9 = 47 —— (3)
x – y = z —– (4)
From (1) (2) (3) and (4)
4A = 58 => A = 14.5
When Rajesh was born, his father age was 29 years older than his Brother and his Mother was 25 years older than his Sister. If his Brother is 2 years elder than his Sister. After 6 years the average age of the family is 20. Then what is the age of Mother when Rajesh was born?- a)27
- b)28
- c)29
- d)30
- e)Cannot be determined
Correct answer is option 'B'. Can you explain this answer?
When Rajesh was born, his father age was 29 years older than his Brother and his Mother was 25 years older than his Sister. If his Brother is 2 years elder than his Sister. After 6 years the average age of the family is 20. Then what is the age of Mother when Rajesh was born?
a)
27
b)
28
c)
29
d)
30
e)
Cannot be determined
|
|
Arya Roy answered |
Answer – 2. 28
Explanation :
Sister = x; Brother = x+2; Father = 29+x+2; Mother = 25+x
Present age – 4x+58
After 6 years
4x+58+30 = 4x+88
4x+88 = 100
x = 3
Mothers age = 25+x = 28.
A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?- a)32 years
- b)36 years
- c)40 years
- d)48 years
Correct answer is option 'C'. Can you explain this answer?
A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?
a)
32 years
b)
36 years
c)
40 years
d)
48 years
|
|
Madhavan Mehta answered |
Given Information:
- Present age of the person is two-fifth of the age of his mother.
- After 8 years, the person will be one-half of the age of his mother.
Let's solve the problem step by step:
Step 1: Assign Variables
Let the present age of the person be P and the present age of the mother be M.
Step 2: Translate the Given Information into Equations
- According to the first condition, P = (2/5)M
- According to the second condition, P + 8 = (1/2)(M + 8)
Step 3: Solve the Equations
Substitute the value of P from the first equation into the second equation:
(2/5)M + 8 = (1/2)(M + 8)
2M + 40 = 5M + 40
3M = 40
M = 40/3
M = 13.33 (approx.)
Step 4: Determine the Mother's Present Age
Therefore, the present age of the mother is approximately 40 years.
Conclusion:
The mother's present age is 40 years.
- Present age of the person is two-fifth of the age of his mother.
- After 8 years, the person will be one-half of the age of his mother.
Let's solve the problem step by step:
Step 1: Assign Variables
Let the present age of the person be P and the present age of the mother be M.
Step 2: Translate the Given Information into Equations
- According to the first condition, P = (2/5)M
- According to the second condition, P + 8 = (1/2)(M + 8)
Step 3: Solve the Equations
Substitute the value of P from the first equation into the second equation:
(2/5)M + 8 = (1/2)(M + 8)
2M + 40 = 5M + 40
3M = 40
M = 40/3
M = 13.33 (approx.)
Step 4: Determine the Mother's Present Age
Therefore, the present age of the mother is approximately 40 years.
Conclusion:
The mother's present age is 40 years.
Eight years ago Ravi’s mother was five times older than her daughter. After Eight years Ravi’s mother will be twice older than her daughter. Find the present age of Ravi?- a)18.33 years
- b)12.5 years
- c)16.7 years
- d)13.33 years
- e)14.5 years
Correct answer is option 'D'. Can you explain this answer?
Eight years ago Ravi’s mother was five times older than her daughter. After Eight years Ravi’s mother will be twice older than her daughter. Find the present age of Ravi?
a)
18.33 years
b)
12.5 years
c)
16.7 years
d)
13.33 years
e)
14.5 years
|
|
Anaya Patel answered |
Eight years ago, Ravi’s age = x
Eight years ago, Ravi’s Mother age = 5x
2(x+16) = 5x+16
2x+32 = 5x+16
x=16/3
Present age of Ravi = 16/3 + 8 = 13.33 years
Eight years ago, Ravi’s Mother age = 5x
2(x+16) = 5x+16
2x+32 = 5x+16
x=16/3
Present age of Ravi = 16/3 + 8 = 13.33 years
Leena’s age is 5 years more than twice Gayathri’s age. Vijay’s age is 13 years less than 10 times Gayathri’s age. If Vijay is 3 times as old as Leena, how old is Leena? - a)17
- b)16
- c)12
- d)14
- e)19
Correct answer is option 'E'. Can you explain this answer?
Leena’s age is 5 years more than twice Gayathri’s age. Vijay’s age is 13 years less than 10 times Gayathri’s age. If Vijay is 3 times as old as Leena, how old is Leena?
a)
17
b)
16
c)
12
d)
14
e)
19
|
|
Nikita Singh answered |
given l = 2g+5
v = 10g-13
v = 3l
f rom v = 3l ⇒ 10g-13 = 6g+15
g = 7
l = 2g+5 = 19
v = 10g-13
v = 3l
f rom v = 3l ⇒ 10g-13 = 6g+15
g = 7
l = 2g+5 = 19
Mr. Sharma has three sons namely Ram, Amit and Karan. Ram is the eldest son of Mr. Sharma while Karan is the youngest one. The present ages of all three of them are square numbers. The sum of their ages after 5 years is 44. What is the age of Ram after three years?- a)15 years
- b)13 years
- c)19 years
- d)17 years
- e)16 years
Correct answer is option 'C'. Can you explain this answer?
Mr. Sharma has three sons namely Ram, Amit and Karan. Ram is the eldest son of Mr. Sharma while Karan is the youngest one. The present ages of all three of them are square numbers. The sum of their ages after 5 years is 44. What is the age of Ram after three years?
a)
15 years
b)
13 years
c)
19 years
d)
17 years
e)
16 years
|
|
Rajeev Kumar answered |
Square numbers – x, y, z
(x + 5) + (y + 5)+ (z + 5) = 44
x + y + z = 44 – 15 = 29
Possible values of x, y, z = 4, 9, 16 [Out of 1, 4, 9, 16, 25] Ram’s present age = 16; after three years = 19
(x + 5) + (y + 5)+ (z + 5) = 44
x + y + z = 44 – 15 = 29
Possible values of x, y, z = 4, 9, 16 [Out of 1, 4, 9, 16, 25] Ram’s present age = 16; after three years = 19
Ravi is as much younger than Surya as he is older than Suresh. If the sum of the ages of Surya and Suresh is 50 years, what is definitely the difference between Surya and Ravi’s age?- a)12 years
- b)23 years
- c)19 years
- d)27 years
- e)Can not be determined
Correct answer is option 'E'. Can you explain this answer?
Ravi is as much younger than Surya as he is older than Suresh. If the sum of the ages of Surya and Suresh is 50 years, what is definitely the difference between Surya and Ravi’s age?
a)
12 years
b)
23 years
c)
19 years
d)
27 years
e)
Can not be determined
|
|
Faizan Khan answered |
Surya’s age – Ravi’s age = Ravi’s age – Surya’s age
Suresh’s age + Surya’s age = 2 Ravi’s age
Surya’s age + Suresh’s age = 50
Ravi’s age = 25; We can not find the difference between Surya and Ravi’s age
Suresh’s age + Surya’s age = 2 Ravi’s age
Surya’s age + Suresh’s age = 50
Ravi’s age = 25; We can not find the difference between Surya and Ravi’s age
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