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All questions of Pipes and Cistern for Bank Exams Exam

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On pipe P is 4 times faster than pipe Q and takes 45 minutes less than pipe Q. In what time the cistern is full if both the pipes are opened together?
  • a)
    8 minutes
  • b)
    10 minutes
  • c)
    12 minutes
  • d)
    14 minutes
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?

Preeti Khanna answered
Let P takes x minutes to fill the tank alone, then Q will take 4x minutes to fill the tank
4x – x = 45, x = 15
So P will take 15 minutes and Q will take 60 minutes to fill the tank. Both will fill the tank in
(60*15)/(75) = 12 minutes

Two pipes A and B can fill a tank in 12 hours and 15 hours respectively. If they are opened on alternate hours with pipe A opened first, then in how many hours the tank will be full?
  • a)
    13 hrs
  • b)
    14 1/2 hrs
  • c)
    12 hrs
  • d)
    12 1/2 hrs
  • e)
    10 2/3 hrs
Correct answer is option 'D'. Can you explain this answer?

Nikita Singh answered
A = 12 hours, B = 15 hours
Total work = LCM(12,15) = 60
So efficiency of A = 60/12 = 5, efficiency of B = 60/15 = 4
2 hrs work of (A+B) = 5+4 = 9
2*6(12) hours work of (A+B) = 9*6 = 54
So remaining work = 60-54 = 6
Now A’s turn at 13th hour, he will do remaining work(6) in 6/12 hr
So total 12 1/2 hrs

In what time would a cistern be filled by three pipes whose diameters are 1cm, 2 cm and 3 cm running together, when the largest pipe alone can fill the tank in 21 minutes? The amount of water flowing through the pipe is directly proportional to the square of its diameter.
  • a)
    10.5 minutes
  • b)
    11.5 minutes
  • c)
    12.5 minutes
  • d)
    13.5 minutes
  • e)
    None of these
Correct answer is option 'D'. Can you explain this answer?

Divey Sethi answered
More the diameter more will be the water flowing through it and less will be the time taken.
Means bigger pipe will take less time to fill the tank
So, for 1 cm time, (12)/(32) = 21/t, we get t = 189
For 2 cm time, (22)/(32) = 21/t. We get t = 189/4
So total time = 1/21 + 1/189 + 4/189 = 2/27
So total time = 13.5 minutes

One pipe fill 1/4 of the tank in 4 minutes and another pipe fills 1/5 of the tank in 4 minutes. Find the time taken by both pipe together to fill half the tank?
  • a)
    40/9 minutes
  • b)
    50/9 minutes
  • c)
    44/9 minutes
  • d)
    53/9 minutes
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?

Chirag Makkar answered
First pipe will take 16 minutes to fill the tank alone. Similarly second pipe will take 20 minutes to fill the tank alone. Let T is the time in which both the pipes will fill half the tank
(1/16 + 1/20)*T = 1/2, we get T = 40/9 minutes

Three pipes A, B, and C can fill the tank in 10 hours, 20 hours and 40 hours respectively. In the beginning all of them are opened simultaneously. After 2 hours, tap C is closed and A and B are kept running. After the 4th hour, tap B is also closed. The remaining work is done by tap A alone. What is the percentage of the work done by tap A alone?
  • a)
    30 %
  • b)
    35 %
  • c)
    45 %
  • d)
    50 %
  • e)
    None of the Above
Correct answer is option 'B'. Can you explain this answer?

Preeti Khanna answered
Pipe A’s work in % = 100/10 = 10%
Pipe B’s work in % = 100/20 = 5%
Pipe C’s work in % = 100/40 = 2.5%
All of them are opened for 2 hours + after 2 hours, tap C is closed + After the 4th hour, tap B is also closed = 100
⇒ (10+5+2.5)*2 + (10+5)*2 + X = 100
⇒ 35 + 30 + work by tap A alone = 100
⇒ work by tap A alone = 100-65 = 35%

In what time a cistern is filled by three pipes of diameter 2cm, 4cm and 6cm respectively. If the time taken by largest pipe to fill the tank is 40 minutes. Amount of water flowing through the pipe is proportional to the diameter of the pipe
  • a)
    25.5/7 min
  • b)
    25.3/7 min
  • c)
    23.5/7 min
  • d)
    23.4/7 min
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?

Alok Verma answered
Given that the diameters of the three pipes are 2 cm, 3 cm and 4 cm
From the given data,
Amount of water from three pipes is 4 units, 9 units and 16 units.
Let the capacity of cistern be 'p' units.
∴ p/58 = 16
⇒ p = 928 units.
In 1 minute, quantity to be filled by 3 pipes = 29 units
∴ Total time required = 928/29 = 32 minutes.

Two pipes P and Q can fill a tank in 10 min and 12 min respectively and a waste pipe can carry off 12 litres of water per minute. If all the pipes are opened when the tank is full and it takes one hour to empty the tank. Find the capacity of the tank.
  • a)
    30
  • b)
    45
  • c)
    60
  • d)
    75
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?

Aarav Sharma answered
Problem:
Two pipes P and Q can fill a tank in 10 min and 12 min respectively and a waste pipe can carry off 12 litres of water per minute. If all the pipes are opened when the tank is full and it takes one hour to empty the tank. Find the capacity of the tank.

Solution:
Let the capacity of the tank be 'x' litres.
Given, Pipe P can fill the tank in 10 minutes. So, the amount of water it can fill in 1 minute is x/10 litres.
Similarly, Pipe Q can fill the tank in 12 minutes. So, the amount of water it can fill in 1 minute is x/12 litres.
The waste pipe can carry off 12 litres of water per minute. So, the net amount of water filled in 1 minute when all pipes are opened is (x/10 + x/12 - 12) litres.
It takes 1 hour to empty the tank. So, the amount of water emptied in 1 minute is x/60 litres.
Therefore, the net amount of water filled in 1 minute is equal to the amount of water emptied in 1 minute. Hence, we can write the equation as follows:
x/10 + x/12 - 12 = x/60
Solving this equation, we get x = 60 litres.

Answer:
The capacity of the tank is 60 litres. Therefore, the correct answer is option (c).

A Tank is filled with the mixture of Milk and Water in the ratio of 3:2 up to 2/5 of its capacity. The tank has two inlet pipes i.e., Milk and Water inlets. Milk and Water pipe can fill an empty tank in 12 and 18 hours respectively. Now both pipes are opened simultaneously and closed after the Tank is completely filled, then what is the ratio of Milk and Water in the full Tank if it can accommodate 250Litre?
  • a)
    1:1
  • b)
    2:3
  • c)
    3:2
  • d)
    5:4
  • e)
    None
Correct answer is option 'C'. Can you explain this answer?

The initial amount of milk and water is :

The amount in the tank before is :

2/5 x 250 = 100 litres 

The amount of water is :

2/5x 100 = 40 litres 

The amount of milk is :

100 - 40 = 60 litres 

The remaining amount is :

250 - 100 = 150 litres 

In 1 hr :

Water = 1/18 of 250 = 125/9

Milk = 1/12 of 250 = 125/6

In 1hr the total amount of milk and water is :

125/9 + 125/6 = (250 + 375) / 18 = 625/18 litres

To fill 150 litres it will take :

150 x 18/625 = 108/25 hrs

In 1 hr The amount of milk is = 125/6

How much water will be there in 108/25 hrs will. 

108/25 x 125/6 = 5 x 18 = 90 litres 
The amount of water is : 150 - 90 = 60litres
The total amount of %
Water = 60 + 40 = 100
Milk = 90 + 60 = 150
Milk : water = 150 : 100
= 3 : 2

Two pipes P and Q can fill a cistern in 10 hours and 20 hours respectively. If they are opened simultaneously. Sometimes later, tap Q was closed, then it takes total 8 hours to fill up the whole tank. After how many hours Q was closed?
  • a)
    4 hours
  • b)
    5 hours
  • c)
    2 hours
  • d)
    6 hours
  • e)
    None of the Above
Correct answer is option 'A'. Can you explain this answer?

Vikas Singh answered
Assume that the total volume of the cistern is 200L.

so, P fills 20L/hr and Q fills 10L/hr, and they both simultaneously fill 30L/hr

now, let Q was closed after x hrs and then rest was filled by P.

30x + 20(8-x)= 200

10x = 40 => x = 4 hrs

hence Q was closed after 4 hrs

A full tank gets emptied in 8 minutes due to the presence of a leak in it. On opening a tap which can fill the tank at the rate of 9 L/min, the tank get emptied in 12 min. Find the capacity of a tank?
  • a)
    120 L
  • b)
    240 L
  • c)
    216 L
  • d)
    224 L
  • e)
    None of the Above
Correct answer is option 'C'. Can you explain this answer?

Aarav Sharma answered
To solve this problem, we can use the concept of rates and proportions. Let's assume the capacity of the tank is 'x' liters.

The leak empties the tank in 8 minutes, which means the leak rate is (x/8) liters per minute.

When the tap is opened, it fills the tank at a rate of 9 liters per minute. So the fill rate is 9 liters per minute.

When both the leak and the tap are open, the effective rate of emptying the tank will be the difference between the leak rate and the fill rate.

So, the effective rate of emptying the tank = (x/8) - 9 liters per minute.

According to the given information, when the tap is open, the tank gets emptied in 12 minutes. Hence, the effective rate of emptying the tank is equal to the fill rate.

(x/8) - 9 = 9

Now, let's solve this equation to find the value of 'x'.

Adding 9 to both sides of the equation, we get:

(x/8) = 18

Multiplying both sides of the equation by 8, we get:

x = 144

Therefore, the capacity of the tank is 144 liters.

Since none of the given options match the answer 144, we can conclude that none of the options provided are correct.

An inlet pipe can fill a tank in 4 hours and an outlet pipe can empty a tank in 3/7 of a tank in 3h. Find the time taken to fill the tank if they start working alternately.
  • a)
    125/8 hours
  • b)
    127/7 hours
  • c)
    121/9 hours
  • d)
    129/8 hours
  • e)
    None
Correct answer is option 'B'. Can you explain this answer?

Nikita Singh answered
Given:
Time taken by inlet pipe to fill the tank = 4 hours
Time taken by outlet pipe to empty 3/7 of a tank = 3 hours
Formula used:
Efficiency = Total work/Time taken
Calculation:
LCM of 4 and 7 = 28 = Total work
Efficiency of inlet pipe = 28/4 = 7 work
Efficiency of outlet pipe = 28/7 = 4 work
Work done in 2 hours = (7 – 4) = 3 work
Time taken to do 27 work = (2/3) × 27 hours
⇒ 18 hours
Time taken more to complete remaining 1 work = 1/7 hour
Total time taken = 18 + (1/7) hours
⇒ 127/7 hours
∴ The total time taken to fill the tank is 127/7 hours

Three taps P, Q and R can fill a tank in 12, 15 and 20 hours respectively. If P is open all the time and Q, R are open for one hour each alternatively, the tank will be full in
  • a)
    3 hours
  • b)
    2 hours
  • c)
    7 hours
  • d)
    4 hours
  • e)
    None of the Above
Correct answer is option 'C'. Can you explain this answer?

Aisha Gupta answered
(P + Q)’s 1 hour work = 1/12 + 1/15 = 3/20
(P + R)’s 1 hour work = 1/12 + 1/20 = 2/15
For 2 hrs = (3/20 + 2/15) = 17/60
For 6 hrs = (3*17/60) = 17/20
Remaining Part = 1 – 17/20 = 3/20 filled by P and Q in 1 hour

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