On pipe P is 4 times faster than pipe Q and takes 45 minutes less than...
Let P takes x minutes to fill the tank alone, then Q will take 4x minutes to fill the tank
4x – x = 45, x = 15
So P will take 15 minutes and Q will take 60 minutes to fill the tank. Both will fill the tank in
(60*15)/(75) = 12 minutes
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On pipe P is 4 times faster than pipe Q and takes 45 minutes less than...
Let P takes x minutes to fill the tank alone, then Q will take 4x minutes to fill the tank
4x – x = 45, x = 15
So P will take 15 minutes and Q will take 60 minutes to fill the tank. Both will fill the tank in
(60*15)/(75) = 12 minutes
On pipe P is 4 times faster than pipe Q and takes 45 minutes less than...
Problem Statement:
Pipe P is 4 times faster than pipe Q and takes 45 minutes less than pipe Q. In what time the cistern is full if both the pipes are opened together?
Solution:
Let's assume that pipe Q takes x minutes to fill the cistern.
Therefore, pipe P will take (x/4) minutes to fill the same cistern.
Given, time taken by pipe P is 45 minutes less than that of pipe Q.
So, we can write the equation as:
x - (x/4) = 45
Solving the above equation, we get:
3x/4 = 45
x = 60
Therefore, pipe Q takes 60 minutes to fill the cistern.
Now, let's find out the time taken by both pipes together to fill the cistern.
Let's assume that the time taken by both pipes together is t minutes.
So, the fraction of work done by pipe Q in 1 minute is 1/60 and the fraction of work done by pipe P in 1 minute is 4/60 = 1/15.
Therefore, the fraction of work done by both pipes together in 1 minute is:
1/60 + 1/15 = 1/12
So, both the pipes together can fill the cistern in 12 minutes.
Hence, the correct answer is option C) 12 minutes.