One pipe fill 1/4 of the tank in 4 minutes and another pipe fills 1/5 ...
First pipe will take 16 minutes to fill the tank alone. Similarly second pipe will take 20 minutes to fill the tank alone. Let T is the time in which both the pipes will fill half the tank
(1/16 + 1/20)*T = 1/2, we get T = 40/9 minutes
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One pipe fill 1/4 of the tank in 4 minutes and another pipe fills 1/5 ...
First pipe will take 16 minutes to fill the tank alone. Similarly second pipe will take 20 minutes to fill the tank alone. Let T is the time in which both the pipes will fill half the tank
(1/16 + 1/20)*T = 1/2, we get T = 40/9 minutes
One pipe fill 1/4 of the tank in 4 minutes and another pipe fills 1/5 ...
To solve this problem, we can calculate the rates at which each pipe fills the tank and then determine the combined rate at which both pipes fill the tank.
Let's start by finding the rate at which each pipe fills the tank.
Pipe 1: Fills 1/4 of the tank in 4 minutes
Pipe 2: Fills 1/5 of the tank in 4 minutes
To find the rates, we can divide the fraction filled by the time taken for each pipe.
Pipe 1 rate = (1/4) / 4 = 1/16 of the tank per minute
Pipe 2 rate = (1/5) / 4 = 1/20 of the tank per minute
Next, we need to determine the combined rate at which both pipes fill the tank. We can add the rates of the two pipes together.
Combined rate = Pipe 1 rate + Pipe 2 rate
Combined rate = 1/16 + 1/20
Combined rate = (5/80) + (4/80)
Combined rate = 9/80 of the tank per minute
Now we can find the time taken by both pipes to fill half the tank. Since the combined rate is given in terms of minutes per tank, we can invert the rate to find the time taken.
Time taken = 1 / (combined rate)
Time taken = 1 / (9/80)
Time taken = 80/9 minutes
Therefore, the time taken by both pipes together to fill half the tank is 80/9 minutes, which is equivalent to option A.