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AMMONIA UNDERGOES SELF DISSOCIATION ACCORDING TO THE RXN 2NH3 (l) ---> NH4 (am) NH2- (am) WHERE am , STANDS FOR AMMONIATED . WHEN 1 MOL OF NH4Cl IS DISSOLVED IN 1 kg OF LIQUID AMMONIA , THE B.P. AT 760 TORR IS OBSV. AT -32.70 C ( NORMAL BOILING B.P OF NH3 (l) IS -33.40 C ) WHAT CONCLUSION IS REACHED ABOUT THE NATURE OF SOLUTION? ( ANS. NH4Cl IS COMPLETELY DISSOCIATED IN NH3) Can someone explain this answer.?
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AMMONIA UNDERGOES SELF DISSOCIATION ACCORDING TO THE RXN 2NH3 (l) --->...
Ans.

Boiling point elevation = (-32.7) - (-33.4) = 0.7
Now according to the given data 
Boiling point elevation = 1000*K(ammonia)*1/1 = 1000*0.00035 = 0.35
So i = 0.7/0.35 = 0.2
So 100 % dissociation
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AMMONIA UNDERGOES SELF DISSOCIATION ACCORDING TO THE RXN 2NH3 (l) --->...
Explanation:

1. Background Information:
- The given reaction shows the self-dissociation of ammonia (NH3) into ammonium ions (NH4+) and amide ions (NH2-).
- The normal boiling point of pure liquid ammonia is -33.40°C at 1 atm.

2. Observation:
- When 1 mol of NH4Cl is dissolved in 1 kg of liquid ammonia, the boiling point at 760 torr is observed to be -32.70°C.

3. Interpretation:
- The fact that the boiling point of the solution is slightly higher than that of pure liquid ammonia indicates that the solution is a non-ideal solution.
- The solution of NH4Cl in liquid ammonia is likely to be highly associated or dissociated due to the deviation from the normal boiling point of ammonia.

4. Conclusion:
- The conclusion reached is that NH4Cl is completely dissociated in liquid ammonia.
- This implies that the NH4Cl molecules break down into NH4+ and Cl- ions in the liquid ammonia solution, leading to a change in the boiling point of the solution.
Therefore, based on the observed boiling point deviation, it can be concluded that NH4Cl is completely dissociated in liquid ammonia, indicating the nature of the solution is highly associated or dissociated.
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AMMONIA UNDERGOES SELF DISSOCIATION ACCORDING TO THE RXN 2NH3 (l) ---> NH4 (am) NH2- (am) WHERE am , STANDS FOR AMMONIATED . WHEN 1 MOL OF NH4Cl IS DISSOLVED IN 1 kg OF LIQUID AMMONIA , THE B.P. AT 760 TORR IS OBSV. AT -32.70 C ( NORMAL BOILING B.P OF NH3 (l) IS -33.40 C ) WHAT CONCLUSION IS REACHED ABOUT THE NATURE OF SOLUTION? ( ANS. NH4Cl IS COMPLETELY DISSOCIATED IN NH3) Can someone explain this answer.?
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AMMONIA UNDERGOES SELF DISSOCIATION ACCORDING TO THE RXN 2NH3 (l) ---> NH4 (am) NH2- (am) WHERE am , STANDS FOR AMMONIATED . WHEN 1 MOL OF NH4Cl IS DISSOLVED IN 1 kg OF LIQUID AMMONIA , THE B.P. AT 760 TORR IS OBSV. AT -32.70 C ( NORMAL BOILING B.P OF NH3 (l) IS -33.40 C ) WHAT CONCLUSION IS REACHED ABOUT THE NATURE OF SOLUTION? ( ANS. NH4Cl IS COMPLETELY DISSOCIATED IN NH3) Can someone explain this answer.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about AMMONIA UNDERGOES SELF DISSOCIATION ACCORDING TO THE RXN 2NH3 (l) ---> NH4 (am) NH2- (am) WHERE am , STANDS FOR AMMONIATED . WHEN 1 MOL OF NH4Cl IS DISSOLVED IN 1 kg OF LIQUID AMMONIA , THE B.P. AT 760 TORR IS OBSV. AT -32.70 C ( NORMAL BOILING B.P OF NH3 (l) IS -33.40 C ) WHAT CONCLUSION IS REACHED ABOUT THE NATURE OF SOLUTION? ( ANS. NH4Cl IS COMPLETELY DISSOCIATED IN NH3) Can someone explain this answer.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for AMMONIA UNDERGOES SELF DISSOCIATION ACCORDING TO THE RXN 2NH3 (l) ---> NH4 (am) NH2- (am) WHERE am , STANDS FOR AMMONIATED . WHEN 1 MOL OF NH4Cl IS DISSOLVED IN 1 kg OF LIQUID AMMONIA , THE B.P. AT 760 TORR IS OBSV. AT -32.70 C ( NORMAL BOILING B.P OF NH3 (l) IS -33.40 C ) WHAT CONCLUSION IS REACHED ABOUT THE NATURE OF SOLUTION? ( ANS. NH4Cl IS COMPLETELY DISSOCIATED IN NH3) Can someone explain this answer.?.
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