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If the maximum kinetic energy of emitted photoelectrons from a metal surface of work function 2.5ev,is 1.7ev.If wavelength of incident radiation is halved, then stopping potential will be 1)2.5v 2)6.7v 3)5v 4)1.1v?
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Explanation:
When a photon of energy, E = hv (where h is Planck's constant and v is the frequency of incident radiation), falls on a metal surface, it transfers its energy to an electron in the metal. If this energy is greater than the work function (ϕ) of the metal, the electron is ejected from the surface with kinetic energy equal to (E-ϕ).
Given data:
Work function (ϕ) = 2.5 eV
Maximum kinetic energy of emitted photoelectrons (KEmax) = 1.7 eV
To find:
Stopping potential (V0) for incident radiation of halved wavelength
Solution:
We know that KEmax = (E-ϕ) where E is the energy of the incident photon. Therefore,
(E-ϕ) = 1.7 eV
E = 1.7 eV + 2.5 eV = 4.2 eV
Now, we can use the equation for stopping potential,
V0 = E/e
where e is the charge of an electron. Substituting the value of E, we get
V0 = 4.2 eV/e = 4.2 V
When the wavelength of incident radiation is halved, the energy of each photon is doubled (since E = hv = hc/λ, where c is the speed of light). Therefore, the energy of each ejected electron will also be doubled, and the stopping potential required to stop these electrons will also be doubled. Hence,
New stopping potential (V0') = 2 x 4.2 V = 8.4 V
Answer: The stopping potential will be 8.4 V. Therefore, the correct option is (2) 6.7 V.
When a photon of energy, E = hv (where h is Planck's constant and v is the frequency of incident radiation), falls on a metal surface, it transfers its energy to an electron in the metal. If this energy is greater than the work function (ϕ) of the metal, the electron is ejected from the surface with kinetic energy equal to (E-ϕ).
Given data:
Work function (ϕ) = 2.5 eV
Maximum kinetic energy of emitted photoelectrons (KEmax) = 1.7 eV
To find:
Stopping potential (V0) for incident radiation of halved wavelength
Solution:
We know that KEmax = (E-ϕ) where E is the energy of the incident photon. Therefore,
(E-ϕ) = 1.7 eV
E = 1.7 eV + 2.5 eV = 4.2 eV
Now, we can use the equation for stopping potential,
V0 = E/e
where e is the charge of an electron. Substituting the value of E, we get
V0 = 4.2 eV/e = 4.2 V
When the wavelength of incident radiation is halved, the energy of each photon is doubled (since E = hv = hc/λ, where c is the speed of light). Therefore, the energy of each ejected electron will also be doubled, and the stopping potential required to stop these electrons will also be doubled. Hence,
New stopping potential (V0') = 2 x 4.2 V = 8.4 V
Answer: The stopping potential will be 8.4 V. Therefore, the correct option is (2) 6.7 V.
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If the maximum kinetic energy of emitted photoelectrons from a metal surface of work function 2.5ev,is 1.7ev.If wavelength of incident radiation is halved, then stopping potential will be 1)2.5v 2)6.7v 3)5v 4)1.1v?
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If the maximum kinetic energy of emitted photoelectrons from a metal surface of work function 2.5ev,is 1.7ev.If wavelength of incident radiation is halved, then stopping potential will be 1)2.5v 2)6.7v 3)5v 4)1.1v? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If the maximum kinetic energy of emitted photoelectrons from a metal surface of work function 2.5ev,is 1.7ev.If wavelength of incident radiation is halved, then stopping potential will be 1)2.5v 2)6.7v 3)5v 4)1.1v? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the maximum kinetic energy of emitted photoelectrons from a metal surface of work function 2.5ev,is 1.7ev.If wavelength of incident radiation is halved, then stopping potential will be 1)2.5v 2)6.7v 3)5v 4)1.1v?.
If the maximum kinetic energy of emitted photoelectrons from a metal surface of work function 2.5ev,is 1.7ev.If wavelength of incident radiation is halved, then stopping potential will be 1)2.5v 2)6.7v 3)5v 4)1.1v? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If the maximum kinetic energy of emitted photoelectrons from a metal surface of work function 2.5ev,is 1.7ev.If wavelength of incident radiation is halved, then stopping potential will be 1)2.5v 2)6.7v 3)5v 4)1.1v? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the maximum kinetic energy of emitted photoelectrons from a metal surface of work function 2.5ev,is 1.7ev.If wavelength of incident radiation is halved, then stopping potential will be 1)2.5v 2)6.7v 3)5v 4)1.1v?.
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