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A trailer is moving along a straight line with a constant acceleration a. A boy standing in the train throws a ball forward with a speed of 10m/s , at an angle of 60degree to the horizontal . The boy has to move forward 1.15m inside the train to catch the ball back at the initial height . The acceleration of the train in m/ s2 is?
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A trailer is moving along a straight line with a constant acceleration...
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A trailer is moving along a straight line with a constant acceleration...
Given:

  • Initial velocity of the ball, u = 10 m/s

  • Angle made by the ball with the horizontal, θ = 60°

  • Displacement of the boy inside the train, s = 1.15 m



To find: Acceleration of the train, a.

Explanation:

  • Let's assume that the train is moving along the positive x-axis, and the ball is thrown in the positive x-direction with an angle of 60° with the horizontal.

  • The horizontal component of the initial velocity of the ball, ux = u cos θ = 10 x cos 60° = 5 m/s.

  • The vertical component of the initial velocity of the ball, uy = u sin θ = 10 x sin 60° = 8.66 m/s.

  • Since the initial vertical position of the ball and the final vertical position of the ball are the same, the vertical displacement of the ball is zero.

  • Therefore, using the formula of displacement, s = uxt + 1/2at2, we can find the time taken by the ball to cover the horizontal distance s.

  • Substituting the values, we get 1.15 = 5t + 1/2at2.

  • Similarly, using the formula of displacement, s = uyt + 1/2at2, we can find the maximum height reached by the ball.

  • Substituting the values, we get h = uyt - 1/2gt2.

  • Since the ball returns to the initial height, h = 0.

  • Using the above two equations, we can eliminate t and get the value of a.



Calculation:

  • 1.15 = 5t + 1/2at2

  • 0 = 8.66t - 1/2gt2



On solving the above equations, we get a = 2.5 m/s2.

Therefore, the acceleration of the train is 2.5 m/s2.
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A trailer is moving along a straight line with a constant acceleration a. A boy standing in the train throws a ball forward with a speed of 10m/s , at an angle of 60degree to the horizontal . The boy has to move forward 1.15m inside the train to catch the ball back at the initial height . The acceleration of the train in m/ s2 is?
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A trailer is moving along a straight line with a constant acceleration a. A boy standing in the train throws a ball forward with a speed of 10m/s , at an angle of 60degree to the horizontal . The boy has to move forward 1.15m inside the train to catch the ball back at the initial height . The acceleration of the train in m/ s2 is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A trailer is moving along a straight line with a constant acceleration a. A boy standing in the train throws a ball forward with a speed of 10m/s , at an angle of 60degree to the horizontal . The boy has to move forward 1.15m inside the train to catch the ball back at the initial height . The acceleration of the train in m/ s2 is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A trailer is moving along a straight line with a constant acceleration a. A boy standing in the train throws a ball forward with a speed of 10m/s , at an angle of 60degree to the horizontal . The boy has to move forward 1.15m inside the train to catch the ball back at the initial height . The acceleration of the train in m/ s2 is?.
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